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konstantin123 [22]

2 years ago

10

PLZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

PP I NEED TO MARK SOM1 BRAINLIEST

1 answer:

densk [106]2 years ago

3 0

1. is 6x im pretty sure

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Evaluate the following expression if y = 4

sleet_krkn [62]

15+5•y/2

15+5•4 / 2

15+20 / 2

15+10

=25

3 0

3 years ago

Evaluate -3(9+y) if y = -7

mario62 [17]

Answer:

-6

Step-by-step explanation:

Substitutet -7 for y in -3(9+y): -3(9 - 7) = -3(2) = -6

6 0

3 years ago

Read 2 more answers

In his garden jim is using cone shape planters for his happing plants has a diameter of of 8 inches and a height of 13 inches he

Dmitry_Shevchenko [17]

Answer:12

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8 0

3 years ago

Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to chec

klasskru [66]

Answer:

There is a horizontal tangent at (0,-4)

The tangent is vertical at (-2,-3) and (2,-3).

Step-by-step explanation:

The given function is defined parametrically by the equations:

$x=t^3-3t$

and

$y=t^2-4$

The tangent function is given by:

$\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\implies \frac{dy}{dx}=\frac{2t}{3t^2-3}$

The tangent is vertical at when $\frac{dx}{dt}=0$

$\implies \frac{3t^2-3}{2t}=0$

$\implies 3t^2-3=0$

$\implies 3t^2=3$

$\implies t^2=1$

$\implies t=\pm1$

When t=1,

$x=1^3-3(1)=-2$ and $y=1^2-4=-3$

When t=-1,

$x=(-1)^3-3(-1)=2$ and $y=(-1)^2-4=-3$

The tangent is vertical at (-2,-3) and (2,-3).

The tangent is horizontal, when $\frac{dy}{dx}=0$ or $\frac{dy}{dt}=0$

$\implies 2t=0$

$\implies t=0$

When t=0,

$x=0^3-3(0)=0$ and $y=0^2-4=-4$

There is a horizontal tangent at (0,-4)

5 0

3 years ago

Help please!! I would appreciate it ❤️

sweet [91]

Answer:

1. a, b, d, e

2. c. Triangles ABE and BAD are congruent

d. Triangles AED and BDE are congruent

Step-by-step explanation:

1. Trapezoid is a quadrilateral which has two parallel opposite sides. Isosceles trapezoid has congruent legs.

Consider all options:

a. Sides AE and BD are congruent (by definition of isosceles trapezoid) - true

b. Sides AB and ED are parallel (by definition of trapezoid) - true

c. AB is not congruent to ED (AB and ED are trapezoid's bases, they are never congruent) - false

d. AE is congruent to BD as legs of isosceles trapezoid - true

e. AB is parallel to ED as bases of trapezoid - true

2. Consider all options:

a. Triangles ABE and DBE are not congruent (ABE is obtuse triangle, DBE is acute triangle)

b. Triangles ABD and DAE are not congruent (ABD is obtuse triangle, DAE is acute triangle)

c. Triangles ABE and BAD are congruent by SAS postulate

d. Triangles AED and BDE are congruent by SAS postulate

e. Triangles EAB and EDB are not congruent (EAB is obtuse triangle, EDB is acute triangle)

5 0

3 years ago