Weaker the intermolecular forces present the less the energy is required to break these forces and change its state from liquid to vapors/gas.
More stronger the intermolecular forces the less the volatile the substance be as the more energy or temperature is required to overcome these intermolecular forces
Four electron shells cause both of them are on the 4th period.
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
<h3>What is Enthalpy of Fusion ?</h3>
The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
<h3>How to find the change in energy ? </h3>
To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) = 
= 
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
Learn more about the Latent heat of fusion here: brainly.com/question/87248
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Answer: Option (b) is the correct answer.
Explanation:
Porosity means the ease with which a fluid can pass through between a rock or cracks etc.
If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.
If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.
Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.
If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.
Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.
I only knwi one way which is if water evaporates from a mixture
