Question

A 20.00 g mixture of magnesium and zinc metal reacting with excess hydrochloric acid produced 1.152 g of hydrogen gas. what is the percent zinc in the original mixture?

Answer 1

percentage of zinc= 5.985/20 X 100= 29.5%

let x represents zinc and y be magnesium so

Zinc(s) + 2HCl(aq) -----> ZnCl2(aq) +  H2(g)

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

1.152 g of hydrogen gas=( x/65.3 + y/24.305) 20

= 3.08 x10^-2 + 0.8295-8.30

=x=5.985

y= 4.015

percentage of zinc= 5.985/20 X 100= 29.5%

The hydrogen gas escapes, so the two products of Zinc Chloride and Magnesium Chloride will then react with Silver Nitrate. Again, I combine both of the reactions

To learn more about zinc:

brainly.com/question/13890062

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