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LiRa [457]
3 years ago
10

Which of the following soils is the most porous? Soil A - flat, sorted particles. Soil B - round, sorted particles Soil C - roun

d, unsorted particles Soil D - flat, unsorted particles
Chemistry
1 answer:
Ksju [112]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

Porosity means the ease with which a fluid can pass through between a rock or cracks etc.

If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.

If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.

Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.

If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.

Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.

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3 years ago
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Answers for Chemistry A/Honors Chem A Unit 2 Test
Ivanshal [37]

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8 0
2 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl
Cerrena [4.2K]

Answer:

0.077 M

Explanation:

Molarity is the representation of the solution.

Molarity:

It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                    M = moles of solute / Liter of solution . . . . . . . . . . (1)

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

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Volume of Solution =  100 g = 100 mL

Volume of Solution in L =  100 mL / 1000

Volume of Solution =  0.1 L

molar mass of NaCl = 58.44 g/mol

Now to find number of moles of Nacl

               no. of moles of NaCl = mass of NaCl / molar mass

               no. of moles of NaCl =  0.45g / 58.44 g/mol

               no. of moles of NaCl =  0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

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Explanation:

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