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LiRa [457]
3 years ago
10

Which of the following soils is the most porous? Soil A - flat, sorted particles. Soil B - round, sorted particles Soil C - roun

d, unsorted particles Soil D - flat, unsorted particles
Chemistry
1 answer:
Ksju [112]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

Porosity means the ease with which a fluid can pass through between a rock or cracks etc.

If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.

If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.

Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.

If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.

Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.

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In the chemical reaction:
velikii [3]

Taking into account the reaction stoichiometry and definition of limiting reactant, AgNO₃ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Cu + 2 AgNO₃  → 2 Ag + Cu(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cu: 1 mole
  • AgNO₃: 2 moles
  • Ag: 2 moles
  • Cu(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Cu reacts with 2 moles of AgNO₃, 1.8 moles of Cu reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3} =\frac{1.8 moles of Cux2 moles of AgNO_{3} }{1 mole of Cu}

<u><em>amount of moles of AgNO₃= 3.6 moles</em></u>

But 3.6 moles of AgNO₃ are not available, 2 moles are available. Since you have less moles than you need to react with 1.8 moles of Cu, AgNO₃ will be the limiting reagent.

<h3>Summary</h3>

In summary, AgNO₃ will be the limiting reagent.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

8 0
1 year ago
An electric motor turns a belt that powers a pump. If this system is compared to the chemical reactions of the cell, which part
den301095 [7]
The electricity on which the motor runs represents ATP.

ATP, adenosine triphosphate, is the energy currency of the cell. The energy released during the process of respiration is stored in the ATP molecule, and the ATP is stored within cells. Whenever the cell requires energy for any function, it simply hydrolyzes the ATP molecule, breaking a phosphate group off and releasing energy in the process.
7 0
3 years ago
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Which of the following is true of groups on the periodic table? A. Groups are horizontal and do not have the same properties. B.
Stells [14]
<span>Groups are vertical, numbered 1 through 18, and have similar properties, so answer D. Most of the properties of groups are defined by the outermost electron in the shells of the elements. Horizontal delineations in the Periodic Table are known as periods.</span>
3 0
3 years ago
The radius of an indium atom is 0.163 nm. If indium crystallizes in a face-centered unit cell, what is the length of an edge of
adoni [48]

<u>Answer:</u> The edge length of the unit cell is 0.461 nm

<u>Explanation:</u>

We are given:

Atomic radius of iridium = 0.163 nm

To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

a=2\sqrt{2}R

Putting values in above equation, we get:

a=2\sqrt{2}\times 0.163=0.461nm

Hence, the edge length of the unit cell is 0.461 nm

8 0
3 years ago
Describe the relationship between the light-dependent and the light-independent reactions.
Slav-nsk [51]
<span>The products of the light-dependent reactions are used to help 'fuel' the light-independent reactions. 

</span><span>Example:
NADPH and ATP are produced during the light-dependent reaction for use in the light-independent reaction (the Calvin Cycle). </span>
3 0
3 years ago
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