<h3>Answer:</h3>
6.21 × 10²² Carbon Atoms
<h3>Solution:</h3>
Data Given:
Mass of Butane (C₄H₁₀) = 1.50 g
M.Mass of Butane = 58.1 g.mol⁻¹
Step 1: Calculate Moles of Butane as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 1.50 g ÷ 58.1 g.mol⁻¹
Moles = 0.0258 mol
Step 2: Calculate number of Butane Molecules;
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Butane Molecules can be written as,
Moles = Number of C₄H₁₀ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹
Solving for Number of Butane molecules,
Number of C₄H₁₀ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹
Putting value of moles,
Number of C₄H₁₀ Molecules = 0.0258 mol × 6.022 × 10²³ Molecules.mol⁻¹
Number of C₄H₁₀ Molecules = 1.55 × 10²² C₄H₁₀ Molecules
Step 3: Calculate Number of Carbon Atoms:
As,
1 Molecule of C₄H₁₀ contains = 4 Atoms of Carbon
So,
1.55 × 10²² C₄H₁₀ Molecules will contain = X Atoms of Carbon
Solving for X,
X = (1.55 × 10²² C₄H₁₀ Molecules × 4 Atoms of Carbon) ÷ 1 Molecule of C₄H₁₀
X = 6.21 × 10²² Atoms of Carbon
