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1 year ago

Chloe and tino have a combined age of 48. three years ago chloe was double the age tino is now. find tinos age

Mathematics

1 answer:

jeka941 year ago

5 0

As given Chole and Tinos age , the present age of Tino is equal to 15 years.

As given,

Let x and y be the present age of Chole and Tino. respectively.

Combined age = 48

Given condition,

x + y = 48 _______(1)

Three years ago

x - 3 = 2y

⇒x =2y +3 _______(2)

Substitute the value of x in (1),

2y+3 +y =48

⇒ 3y = 45

⇒ y = 15years

Therefore , as given Chole and Tinos age , the present age of Tino is equal to 15 years.

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Read 2 more answers

Csc (2sin^-1(-12/13))<br> that is 2 times inverse sin of -12/13

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Answer: $-\frac{169}{120}$

I'm assuming you mean this:

$cosec(2sin^{-1}(\frac{-12}{13}))$

Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

$\frac{1}{sinx}$

So, using the sine relationship:

$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}$

Let $u = sin^{-1}(\frac{-12}{13})$
$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}$
$= \frac{1}{2sinu \cdot cosu}$
$= \frac{1}{2sin(sin^{-1}(\frac{-12}{13})) \cdot cos(sin^{-1}(\frac{-12}{13}))}$
$= \frac{1}{\frac{-24}{13} \cdot \sqrt{1 - (\frac{-12}{13})^{2}}}$
$= \frac{1}{\frac{-24}{13}} \cdot \frac{1}{\sqrt{1 - \frac{144}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\sqrt{\frac{25}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\frac{5}{13}}$
$= -\frac{13}{24} \cdot \frac{13}{5}$
$= -\frac{169}{120}$

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