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sattari [20]
2 years ago
10

$32.00for a 14 2/9 km taxi ride. What is the cost per kilometer

Mathematics
1 answer:
KonstantinChe [14]2 years ago
4 0

\begin{array}{ccll} \$&km\\ \cline{1-2} 32&14\frac{2}{9}\\[1em] x&1 \end{array}\implies \cfrac{32}{x}=\cfrac{14\frac{2}{9}}{1}\implies \cfrac{32}{x}=14\frac{2}{9}\implies \cfrac{32}{x}=\cfrac{14\cdot 9+2}{9} \\\\\\ \cfrac{32}{x}=\cfrac{128}{9}\implies 288=128x\implies \cfrac{288}{128}=x\implies \stackrel{~\hfill \textit{2 bucks and 25 cents}}{\cfrac{9}{4}=x\implies 2\frac{1}{4}}=x

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Answer:

P(A∩B) = 0.522

Step-by-step explanation:

Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years

So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:

P(A∩B) = P(A)*P(B/A)

Because A and B are not independents.

Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.

Finally, replacing the values, we get:

P(A∩B) = 0.58*0.9 = 0.522

It means that the 52.2% of the puppies are adopted and live 7 or more years.

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