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Komok [63]
1 year ago
9

Which represents the copernican model that is most similar to that of aristarchus?

SAT
1 answer:
jeyben [28]1 year ago
5 0

The Copernican model that is most similar to that of Aristarchus is where the solar system shows the planets in their orbits around the sun in the order: Mercury, Venus, Earth with Moon, Mars, Jupiter, Saturn.

Aristarchus of Samos was a Greek astronomer who argued that the earth rotates on its axis and revolves around the sun. He had suggested a new theory that, if true, would make the universe much larger than was believed at the time. In the 16th century, Aristarchus inspired the Polish astronomer Nicholas in his Copernicus’s studies.

However, Copernicus later erased this reference, and Aristarchus' theory was not mentioned in the book published by him. Copernicus His model is the system of planetary motion maintained by Copernicus, in which the earth revolves once in a day and around the sun once in his year, while the other planets also has an orbit centered near the sun.

Know more about Copernican model here

brainly.com/question/12624338

#SPJ4

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dmitriy555 [2]

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<h3>How to calculate the Cartesian plane?</h3>

Just draw two lines: one of them vertical, starting from the point until it finds the x axis; another horizontal, starting from the point until it meets the y-axis.

Then plotting the value of X on the graph we find the following for each value of X to Y:

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See more about coordinates at brainly.com/question/23450276

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2 years ago
Which forceps would be a good choice for holding fascia?
mamaluj [8]

Answer:

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Explanation:

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3 years ago
A tortoise and a hare engage in a race. A tortoise can run with a speed of 0. 15 m/s. A hare can run 25 times as fast as the tor
Nonamiya [84]

Let D be the total length of the race, and T the time it takes for the tortoise to finish it. Then

D = (0.15 m/s) T

Let t be the time after the start of the race when the hare decides to take a nap. In this time, the tortoise travels a distance

(0.15 m/s) t

and the hare travels

25 (0.15 m/s) t = (3.75 m/s) t

For the next 5.0 min = 300 s, the tortoise keeps moving and covers a distance of

(0.15 m/s) (300 s) = 45 m

while the hare covers no distance.

After these 300 seconds, the remaining time for the tortoise to complete the race is (T - t - 300 s). In this same time, the hare loses the race by 35 cm = 0.35 m, so overall it has covered a total distance of

(3.75 m/s) t + 0 (300 s) + (3.75 m/s) (T - t - 300 s) = D - 0.35 m

Solve for T :

(3.75 m/s) t + 0 + (3.75 m/s) T - (3.75 m/s) t - 1125 m = D - 0.35 m

(3.75  m/s) T - 1125 m = D - 0.35 m

(3.75 m/s) T - 1125 m = (0.15 m/s) T - 0.35 m

(3.60 m/s) T = 1124.65 m

T = 312.403 s

(b) So, the race takes about 312 seconds, or 5.21 minutes.

(a) It also follows that the race has a total length of

D = (0.15 m/s) (312.403 s) ≈ 46.9 m

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