Question

A gold mine has two​ elevators, one for equipment and another for the miners. The equipment elevator descends 4 feet per second. The elevator for the miners descends 15 feet per second. One​ day, the equipment elevator begins to descend. After 28 ​seconds, the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 17 ​seconds? At that​ time, which elevator is​ deeper?

Answer 1

The miners elevator is deeper than that of the equipment.

How to calculate the speed of elevator?

Speed of the equipment elevator is been given as  4 feet per second and Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = (30 + 14)  = 44 seconds

   Then,   distance  can be calculated as (speed x time) which equals to  = 4 x 44 = - 176 ft            

but  distance of the miners elevator after 14 seconds is:

speed = (15 x 17)    = 225

therefore,   distance = - 225 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 225 feet (-225 feet) below the surface.

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