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3 years ago

Two numbers have a sum of 32. One number is 6 more than the other. Find the numbers

Mathematics

2 answers:

Vlad [161]3 years ago

5 0

<h2>Answer: 13 & 19</h2>

<h3>Step-by-step explanation:</h3>

Let the bigger number be 'U' and the smaller number 't'.

Since the two numbers have a sum of 32, then U + t = 32.

& since one number is 6 more than the other, the U - 6 = t

⇒ U + U - 6 = 32

2U = 38

U = 19

By substituting fot the value of U we found,

19 - 6 = t

t = 13

<h3>∴ the numbers are 13 & 19.</h3>

Bad White [126]3 years ago

4 0

Answer:

13 and 19

Step-by-step explanation:

let's first set the two mystery numbers as "x"

and we know that x + (x + 6) = 32 since one of the numbers is 6 more than the other.

now let's set it up:

x + x + 6 = 32

= 2x = 26

= x = 13

so we know that x = 13 now we need to find the other number so we do:

13 + 6 = 19

now to check our work:

13 + 19 = 32

hope that helped :))

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For what values of the variables are the following expressions defined? 1. 5y+2 2. 18/y 3. 1/x+7 4. 2b/10−b Example: X>7

Serga [27]

Answer:

1. All real numbers

2. All real numbers except y = 0

3. All real numbers except x = -7

4. All real numbers except b = 10

Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em> $\infty$ <em> or it should not give us the </em> $\frac{0}{0}$ <em> (zero by zero) form </em> when the input is given to the function.

The value of function will depend on the denominator.

Now, let us consider the given functions one by one:

1. 5y+2

Here denominator is 1. So, it can not attain a value $\infty$ or $\frac{0}{0}$ <em> (zero by zero) form </em>

So, for all real numbers, the function is defined.

$2.\ \dfrac{18}{y}$

At y = 0, the value

$At\ y =0, \dfrac{18}{y} \rightarrow \infty$

So, the given function is <em>defined for all real numbers except y = 0</em>

<em></em> $3.\ \dfrac{1}{x+7}$ <em></em>

Let us consider denominator:

x + 7 can be zero at a value x = -7

$At\ x =-7, \dfrac{1}{x+7} \rightarrow \infty$

So, the given function is <em>defined for all real numbers except x = -7</em>

$4.\ \dfrac{2b}{10-b}$

Let us consider denominator:

10-b can be zero at a value b = 10

$At\ b =10, \dfrac{2b}{10-b} \rightarrow \infty$

So, the given function is <em>defined for all real numbers except b = 10</em>

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3 years ago

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deff fn [24]

28 hope that helped...

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Mariana [72]

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(

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2 years ago

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Vikentia [17]

In the comment of the other answer, you said that the rectangle is 24 x 18 ft.

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4 years ago

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LuckyWell [14K]

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3 years ago