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4vir4ik [10]
3 years ago
10

82= 2( 1-8p) step by step

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0
82÷2=2÷2(1-8p)
41=(1-8p)
41=1-8p
41-1=1-1-8p
40=8p
40÷8=8p÷8
5=p
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One car traveled 248 and drove 5 mph slower than a second car which drove 268m / (les) . the cars were traveling for the same ,
Katyanochek1 [597]

Answer:

The first car is traveling at a speed of

s1=62 mi/hr.

The second car is traveling at a speed of s2=67 mi/hr.

Step-by-step explanation:

Let t be the amount of time the cars are traveling

s1=248/t and s2=268/t

We are told:

s1=s2-5

That is

248/t=268/t-5

⇒248=268- 5t

⇒5t=20

⇒t=4

s1=248/4=62

s2=268/4=67

4 0
3 years ago
74.34 is 63% of what amount
motikmotik
<span>46.8342 is 63% of 74.34</span>
4 0
4 years ago
Plz plz plz help I will cry if u help this is the last question plz help
vaieri [72.5K]

Answer:

\frac{2}{3}

Step-by-step explanation:

8 0
3 years ago
What is the measure of angle x? Enter your answer in the box
Marta_Voda [28]

Answer: 83

Step-by-step explanation:

A triangle is always 180 degrees

You know the measure of 2 angles (44 and 53).  You need the 3rd.

180 - 44 - 53 = 83

3 0
3 years ago
How much money do I need now if I am going to recieve $5000 every 6 months (starting in 6 months) for 10 years if the interest r
NikAS [45]

He needs to have $205783 amount of money to receive  $5000 every 6 months for 10 years.

<h3>What is Interest ?</h3>

Interest is the amount of money received , when a certain lump sum amount is deposited.

It is given that the person is receiving  ,

Interest = $5000 ,

after six months , every six month

Time Period = 10 years

Interest Rate = 4%

Compounded Semiannual

Let the principal amount be $x

Compound Interest is given by

Amount = P[ 1 + r/n]ⁿˣ

Here x is the time period

Therefore the Amount = x{ 1 +0.04/2}²⁰

x + 5000 *20 = x{ 1 +0.04/2}²⁰

x + 100000 = 1.486 x

x = $205783

Therefore he needs to have $205783 amount of money to receive  $5000 every 6 months for 10 years.

To know more about Interest

brainly.com/question/13324776

#SPJ1

6 0
2 years ago
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