Question

One car traveled 248 and drove 5 mph slower than a second car which drove 268m / (les) . the cars were traveling for the same , how fast was each car traveling ? Show all work

Answer 1

Answer:

The first car is traveling at a speed of

s1=62 mi/hr.

The second car is traveling at a speed of s2=67 mi/hr.

Step-by-step explanation:

Let t be the amount of time the cars are traveling

s1=248/t and s2=268/t

We are told:

s1=s2-5

That is

248/t=268/t-5

⇒248=268- 5t

⇒5t=20

⇒t=4

s1=248/4=62

s2=268/4=67