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Dmitry [639]
3 years ago
13

If the triangles below are similar, find the value of x. 42 х 11 22

Mathematics
1 answer:
stepan [7]3 years ago
3 0

9514 1404 393

Answer:

  28

Step-by-step explanation:

Corresponding sides are proportional.

  x/42 = 22/(22+11)

  x = 42(2/3)

  x = 28

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What is 6 to the 8th power simplified??<br>hurry help me!!​
Delicious77 [7]

Answer:

6^{8}

Step-by-step explanation:

Di ako sure sa sagot ko.

(I'm not sure with my answer)

6 0
3 years ago
The asymptote of the function f(x) = 3x + 1 – 2 is ___. Its y-intercept is ___.
Svetradugi [14.3K]
The only way this could have an asymptote, either horizontal, vertical, or oblique is if it is a rational function, proper or improper. This function is linear:
y=3x-1 is what it simplifies to and it is a straight line through the y axis at -1 and has a positive slope of 3. There are no asymptotes here. But the y intercept, like I stated, is (0, -1)
8 0
3 years ago
What's the area of the triangle with 9mm 76mm 100mm
svlad2 [7]

9514 1404 393

Answer:

  342 mm²

Step-by-step explanation:

The triangle shown has a base of 9 mm and a height of 76 mm. Its area is ...

  A = 1/2bh

  A = (1/2)(9 mm)(76 mm) = 342 mm²

The triangle shown has an area of 342 mm².

_____

<em>Additional comment</em>

The other leg of the right triangle with one leg 76 mm and hypotenuse 100 mm will be about 65 mm. The base shown is 9 mm, so any triangle with the dimensions shown will be a fairly skinny obtuse triangle, not the acute triangle in the picture. (This makes us suspect an error: the 9 mm dimension maybe should be 90 mm.)

3 0
3 years ago
If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found
Goshia [24]
(24ba^2)/(8ab^2)=3a/b=width
5 0
4 years ago
Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
4 years ago
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