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11111nata11111 [884]
2 years ago
8

Perfect pizza has 16 toppings listed on their menu. how many ways could a customer choose a pizza that contains 5 different topp

ings?
Mathematics
1 answer:
marishachu [46]2 years ago
3 0

Answer:

4368 ways

Step-by-step explanation:

Use nCk for this. 16C5. This is \frac{n!}{(n-k)!(k!)}. This becomes\frac{16!}{(11!)(5!)}. This is \frac{16*15*14*13*12}{5*4*3*2*1} due to 16! and 5! canceling out. This becomes 4368.

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Combine like terms: 3x + 11y - 10z - 5y - 4z + 12x
Ivan
Hello there!

First, let's categorize our monomials with the proper variables.

3x + 12x
11y - 5y
-10z -4z

Now, we can make these into simpler terms by adding/subtracting the sectioned variables.

3x + 12x = 15x
11y - 5y = 6y
-10z - 4z = -14z

Now let's place our results into an expression as a final answer.

15x + 6y - 14z is your final expression.

I hope this helps!
7 0
3 years ago
Review the proof.
andrezito [222]

Answer:

Step-by-step explanation:

A 2-column table with 8 rows. Column 1 is labeled Step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine (2 x) = 1 minus 2 sine squared (x), let 2 x = theta, then x = StartFraction theta Over 2 EndFraction, cosine (theta) = 1 minus 2 sine squared (StartFraction theta Over 2 EndFraction), negative 1 + cosine (theta) = negative 2 sine squared (StartFraction theta Over 2 EndFraction), 1 + cosine (theta) = 2 sine squared (StartFraction theta Over 2 EndFraction), StartFraction 1 minus cosine (theta) Over 2 EndFraction = sine squared (StartFraction theta Over 2 EndFraction), sine (StartFraction theta Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 minus cosine (theta) Over 2 EndFraction EndRoot.

Which step contains an error?

Answer:

 

Step-by-step explanation:

 

7 0
3 years ago
Read 2 more answers
PLSSS HELP IF YOU TURLY KNOW THISS
Salsk061 [2.6K]

Answer:

they are not equivalent

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Can someone help explain this solution to me?
TiliK225 [7]
Uh, that looks really complicated lol so u don’t think I’d be able to. Sorry ☹️
5 0
4 years ago
Two garden plots are to have the same area. One is square and one is rectangular. The rectangular plot is 4 meters wide and 16 m
AlexFokin [52]

side = 8 m

the area of the rectangle = length × width = 16 × 4 = 64 m²

the area of the square = s² ( where s is the length of a side ), hence

s² = 64 ( since areas are equal )

take the square root of both sides

s = √64 = 8 m


7 0
3 years ago
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