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11111nata11111 [884]
2 years ago
8

Perfect pizza has 16 toppings listed on their menu. how many ways could a customer choose a pizza that contains 5 different topp

ings?
Mathematics
1 answer:
marishachu [46]2 years ago
3 0

Answer:

4368 ways

Step-by-step explanation:

Use nCk for this. 16C5. This is \frac{n!}{(n-k)!(k!)}. This becomes\frac{16!}{(11!)(5!)}. This is \frac{16*15*14*13*12}{5*4*3*2*1} due to 16! and 5! canceling out. This becomes 4368.

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