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zheka24 [161]
2 years ago
14

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bo

ttles could 10 such machines produce in 4 minutes?.
Business
1 answer:
mariarad [96]2 years ago
6 0

The number of bottles produce by  10 machines in 4 minute are 1800 bottles.

The total number of bottles produced by 6 machines per minute = 270

Number of bottles produced by 1 machine in one minute =270/6

                                                                                               = 45bottles

Number of bottles produced by 10 machines in 4 minute = 45*10*4

                                                                                               =1800 bottles

Production is defined as the process of converting of inputs into the output.

To know more about production:

brainly.com/question/14616889

#SPJ4

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If the price was to rise to $16 quarters then the loads of laundry that each shift would pay for is 112 loads

<h3>How many loads would each shift pay for?</h3>

The amount earned for shift of 75 minutes is:

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= $18

If the cost per load rises to 16 quarters, the number of loads you can afford is:

= Amount earned / cost per load

= 18 / 0.16

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Rest of the question is:

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Who is the president's chief adviser on intelligence matters across the executive branch?
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The Director of National Intelligence is known as the President's chief adviser on intelligence matters across the executive branch.

<h3>What is the role of Director of National Intelligence?</h3>

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A subcontractor is responsible for outfitting six satellites that will be used for solar research. Four of the six have been com
BlackZzzverrR [31]

Answer: ∑Tₓ = 201.222

time required to complete the last two units is 201.222 minutes

Explanation:

Given that,

total time required to four units is 600 hours,

Learning curve applied is 75% and from the learning curve coefficient table, total time factor to complete four units at 75% learning curve is 2.946

so

∑Tₙ = T₁ × total time factor

{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }

we substitute

∑T₄ = ∑T₁ × total time factor

600 = ∑T₁ × 2.946

∑T₁  = 600/2.946

∑T₁  = 203.666 minutes

Now to get the total time required to complete 6 units, we say:

∑T₆ = ∑T₁ × total time factor

Note that total time factor at this point changes;

( from the learning curve coefficient table, total time factor to complete 6 units at 75% learning curve is 3.934)

so we substitute

∑T₆ = 203.666 × 3.934

∑T₆ = 801.222

Now to find how long should it take them to finish the last two units, we say

∑Tₓ = ∑T₆ - ∑T₄

∑Tₓ = 801.222 - 600

∑Tₓ = 201.222

Therefore time required to complete the last two units is 201.222 minutes

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