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1 year ago

Simplify and explain (step by step)

Mathematics

1 answer:

Ad libitum [116K]1 year ago

5 0

Answer:

3u⁵

Step-by-step explanation:

$\sqrt[3]{27}\sqrt[3]{u^{15}}=3u^5$

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What is cosA for this triangle? 48/55 55/73 55/48 48/73

mash [69]

For this case we must indicate the cosine of A, of the figure shown. By definition:

$Cosine (A) = \frac {Cateto\ adjacent\ to\ the \ angle} {hypotenuse}$

Substituting the values we have:

$Cosine (A) = \frac {48} {73}$

So, we have to:

$Cosine (A) = \frac {48} {73}$

Answer:

Option D

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3 years ago

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Can someone help me on this plzzz

choli [55]

Answer:

b=15

How I got it:

32 + (7x4) = 32 + 28 = 60

60 divided by 4 = 15

Checking:

15 - 7 = 8

8 x 4 = 32

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You can tell b = 15 is the correct answer.

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What is the measure of angle x, In degrees? Helps please!!

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Because segments XY and XZ are of equal length, angle Y and angle Z must be congruent.

All inner angles must add to 180 degrees since it's a triangle.
70+70+x=180
140+x=180
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Final answer: D

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3 years ago

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Find the z-score such that the area under the standard normal curve to the left is 0.79.

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Step-by-step explanation:

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3 years ago

Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company

erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that $n = 16$

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that $p = 0.5$

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0$

$P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002$

$P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018$

$P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105$

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

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3 years ago