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1 year ago

7

Just need help on 29

1 answer:

luda_lava [24]1 year ago

6 0

Answer:

b.is the answer to your question

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Solve x2 − 12x + 5 = 0 using the completing-the-square method. x = six plus or minus the square root of five x = negative six pl

Andru [333]

we are given

$x^2-12x+5=0$

we have to solve it by completing square method

step-1: Move 5 on right side

$x^2-12x+5-5=0-5$

$x^2-12x=-5$

step-2: Break middle term

$x^2-2*6*x=-5$

step-3: Add 6^2 both sides

$x^2-2*6*x+(6)^2=-5+(6)^2$

$(x-6)^2=31$

step-3: Solve for x

$\sqrt{(x-6)^2} =\sqrt{31}$

we wil get two values

First value is

$x-6=\sqrt{31}$

add both sides 6

$x-6+6=6+\sqrt{31}$

$x=6+\sqrt{31}$

Second value is

$x-6=-\sqrt{31}$

add both sides 6

$x-6+6=6-\sqrt{31}$

$x=6-\sqrt{31}$

so, solutions are

$x=6+\sqrt{31}$

$x=6-\sqrt{31}$ .............Answer

5 0

3 years ago

1. whats the midpoint between (7,3) and (-3,-1)

Elanso [62]

Answer:

(2, 1 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

Here (x₁, y₁ ) = (7, 3) and (x₂, y₂ ) = (- 3, - 1) , then

midpoint = ( $\frac{7-3}{2}$ , $\frac{3-1}{2}$ ) = ( $\frac{4}{2}$ , $\frac{2}{2}$ ) = (2, 1 )

5 0

3 years ago

Just need help with number 2 I will GUVE brainliest

FinnZ [79.3K]

The answer is a and d

7 0

2 years ago

PLZ!!!!HELP!!!What is the absolute deviation for 15 in the data set?

Brut [27]

20 + 20 + 30 + 15 + 40 = 125
125/5= 25
25-15 = 10
Absolute deviation for 15 is 10

5 0

3 years ago

Read 2 more answers

Please help thank u<br> i will give 15 points + branliest

FromTheMoon [43]

Answer:

the answer is d

Step-by-step explanation:

its the only answer that makes sense in my opinion

7 0

3 years ago

Read 2 more answers