2x+y=9
3x+5y=19
I will do this problem in 2 ways. I.)Substitution II.)Elimination
Solution I.) Substitution
We can subtract 2x from both sides in the first equation.
y=9-2x
Now we can substitute the y in the second equation with 9-2x
3x+5(9-2x)=19
-7x+45=19
-7x=-26
x=26/7
y=9-2(26/7)=11/7
Solution II.)Elimination
We can multiply both side of first equation by 5 to get a 5y in both equations.
10x+5y=45
Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.
(10x+5y)-(3x+5y)=45-19
7x=26
x=26/7
2*26/7+y=9
y=11/7
Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.
I think they should say they last name
-27 divided by 9 = -3, 4 x -6 = -24, 12 x -10 = -120, -45 divided by -5 = 9, 7 x -3 = -21, 72 divided by -8 = -9, 64 dibided by 8 is 8, and -8 x 6 is -48. good luck!! ^_^
The area of the rectangle ACEG is the amount of space on it, and the area of square HJFG is 9 square units
<h3>How to determine the area of the figures?</h3>
The area of a rectangle is:
Area = Length * Width
The area of a square is:
Area = Length * Length
From the question, the given parameters are:
AB =AH = x ;
BC=5;
HG=3
This means that the area of square HJFG is:
Area = HG * HG
Area = 3 * 3
Area = 9
<em>Note that the other areas cannot be calculated because the question is incomplete</em>
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Read more about areas at:
brainly.com/question/17335144
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