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3 years ago

Plz help me Much appreciated.

Mathematics

1 answer:

Ratling [72]3 years ago

8 0

Slope is -12 and the form is y=Mx+b

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Solve the equation 4\pi =w-6\pi

maksim [4K]

Answer:

4/pi=w-6/pi

4 = w-6

Pi pi

Cross mutiply

Pi(w-6)=4(pi)

Wpi - 6pi =4pi

Collect like terms

Wpi=4pi + 6pi

Wpi =10pi

Divide both sides by pi

Wpi = 10pi

Pi pi

W = 10

5 0

3 years ago

Let f(x)=x^2+5x-36. Enter the x-intercepts of the quadratic function in the boxes.

Kipish [7]

Answer:

X Intercepts: (4,0) and -9,0

Step-by-step explanation:

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3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago

Can someone please help

bija089 [108]

Answer:

answer is 1 x( x-4) ok to mmma abhi tak school ki chuti h or bina kisi ne bhi roka aur wo phle h to time but only a few days after lady Catherine visit the gentleman arrived early in the given it most unwillingly

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3 years ago

The formula for the perimeter of a rectangle is p=2(1+w) solve for w.

Dvinal [7]

P=2*(l+w)
p=2l+2w
2w=p - 2l
w= (p-2l)/2

3 0

3 years ago