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ivanzaharov [21]
1 year ago
14

If the quotient of a number and 6 is added to 1/3, the result is 7/6. Find the number.

Mathematics
1 answer:
lisabon 2012 [21]1 year ago
3 0

The number is 4.

<h3>What is the Quotient?</h3>

A quotient is defined as the outcome of dividing an integer by any divisor that can be said to be a quotient. The dividend contains the divisor a specific number of times.

Let n be the number in question; then, we can write the word problem as an equation like this:

⇒ (n/6) + 1/3 = 7/6

Multiply everything by the least common multiple of all the denominators (6, 3, 6), which is 6.  

⇒ 6(n/6) + 9(1/3) = 6(7/6)

⇒ n + 3 = 7

Subtract 3 from both sides,

⇒ n = 4

Hence, the number is 4.

Learn more about the quotient here:

brainly.com/question/27796160

#SPJ1

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the perimeter of a rectangle is 55 inches. the ratio of the length to width is 7:4. use proportions to find the area of the rect
Leni [432]

Answer:

Step-by-step explanation:

let : x the length and y the width    .... ( x  > y and x ; y reals numbers )

the perimeter is : 2(x+y)

2(x+y) = 55...(1)

x/y = 7/4 ...(2)

by (2) : x = (7/4)y

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4 0
3 years ago
Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
-55y=-55
y=1

Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
5 0
3 years ago
A, b and c are the sides of a right triangle, where side a is across from angle a, side b is across from angle b, and side c is
Vera_Pavlovna [14]
<span>Find missing length :
</span>
a² + b² = c²
c² = 19² + 34²
c² = 1517
c = √1517
c = 38.95 units.


Find missing angle A:

\dfrac{a}{\sin(a)} =  \dfrac{c}{\sin(c)}

\dfrac{19}{\sin(a)} =  \dfrac{38.95}{\sin(90)}

\sin(a) = 0.488

a = sin^{-1} (0.488)

a = 29.2 \textdegree


Find Missing B:

\dfrac{b}{\sin(b)} = \dfrac{c}{\sin(c)}

\dfrac{34}{\sin(b)} = \dfrac{38.95}{\sin(90)}

\sin(b) = 0.873

b = sin^{-1}(0.873)

b = 60.8 \textdegree


Answer: Missing length =  38.95 units ; Missing angles =  29.2°  and  60.8° 

8 0
3 years ago
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