Since ur using r as a variable the answer is r = 7.
The amount of water that has entered the pool over these five minutes is 42.5 gallons.
Given the rate at which water enter the pool W(t). To calculate the amount of water that has entered the pool over these five minutes, we integrate W(t) over the interval t = 0 to t = 5.
![Amount\ of \ water=\int\limits^0_5 {W(t)} \, dt \\\\\\Amount\ of \ water=\int\limits^0_5 {(1+3t)} \, dt \\\\\\Amount\ of \ water=[t+1.5t^2]_0^5\\\\\\Amount\ of \ water=42.5\ gallons](https://tex.z-dn.net/?f=Amount%5C%20of%20%5C%20water%3D%5Cint%5Climits%5E0_5%20%7BW%28t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D%5Cint%5Climits%5E0_5%20%7B%281%2B3t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D%5Bt%2B1.5t%5E2%5D_0%5E5%5C%5C%5C%5C%5C%5CAmount%5C%20of%20%5C%20water%3D42.5%5C%20gallons)
The amount of water that has entered the pool over these five minutes is 42.5 gallons.
Find out more on integration at: brainly.com/question/23976638
Answer:
<h2>7y² - 6y -17</h2>
Step-by-step explanation:
(-2y^2-11y-7)-(-9y^2-5y+10) (firstly, we remove the brackets)
-2y^2 - 11y - 7 + 9y^2 + 5y - 10
= (-2y^2 + 9y^2) + (-11y + 5y) + (-7 - 10)
= (7y²) + (-6y) + (-17)
Answer: 60
5 / 2
= 5×4×3×2×1/2×1
=120 / 2
= 60.
I hoped this helped! :)
Possibly d, because it’s a reflection