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inn [45]
2 years ago
6

4(r+3)-3r=19 help me plz

Mathematics
2 answers:
bulgar [2K]2 years ago
6 0
Since ur using r as a variable the answer is r = 7.
ozzi2 years ago
6 0
Solve for r by simplifying both sides of the equation, then isolating the variable.
r = 7
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A scientist measured the width of a square flake of gold to be7.3 x 10 -4mm what is the area of the flake
irakobra [83]

The area of square flake of gold is 53.29 \times 10^{-8} \mathrm{mm}

<h3><u>Solution:</u></h3>

Given that width of square flake of gold is 7.3 \times 10^{-4} millimeter

To find : Area of square flake

Since gold flake is in shape of square, we can use area of square formula

<em><u>The formula for area of square is given as:</u></em>

area = s^2

where "s" is the length of one side

\begin{array}{l}{\text { Area of a square flake }=\left(7.3 \times 10^{-4}\right) \times\left(7.3 \times 10^{-4}\right)} \\\\ {\text { Area of a square flake }=53.29 \times 10^{8}}\end{array}

Hence , the calculated area of flake is 53.29 \times 10^{-8} \mathrm{mm}

7 0
2 years ago
B=(2x+3)(4x^2-6x+9)-2(4^3-1)
nexus9112 [7]
B = (2x+3)(4x^2-6x+9)-2(4^3-1)
B = 8x^3-99

Hope it helps : )
5 0
1 year ago
the davis family pays $200,000 for a new house they make a down payment that is 1/10 of the price of the house how much is the d
Aleksandr-060686 [28]
It is twenty thousand dollars
8 0
3 years ago
Read 2 more answers
Help quick please!!
Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0
2 years ago
Chose one value for x and substitute the value in the equation to get your answer pick x=15 or x=12 or x=10 2x+13
lora16 [44]
If I pick 10, then 2(10)+13=33
If I pick 15, then 2(15)+13=43
If I pick 12, then 2(12)+13=37
8 0
3 years ago
Read 2 more answers
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