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JulijaS [17]
2 years ago
10

Open the cpt manual to the page that contains code 40490. what section of the cpt coding manual is this code listed in?

Mathematics
1 answer:
klasskru [66]2 years ago
8 0

The section of the CPT coding manual is the code 40490 is listed in is "digestive system."

<h3>What is CPT codes?</h3>

CPT is the language used by providers and payers when billing medical procedures and services for reimbursement.

Some key features regarding the CPT codes are-

  • CPT or Current Procedural Terminology, is a set of medical codes used to describe the procedures and services performed by physicians, allied health care professionals, provided by trained practitioners, healthcare facilities, outpatient facilities, and laboratories.
  • CPT codes, in particular, are used to notify services and procedures to both federal and private payers for repayment of rendered healthcare services.
  • CPT codes were developed by the American Medical Association (AMA) in 1966 to standardize reporting of medical, surgery, and diagnosis and treatment procedures and services performed in both inpatient and outpatient settings.
  • Each CPT system defines a written description of a process or service, removing the need for the patient's subjective interpretation of what was provided.

To know more about the CPT codes, here

brainly.com/question/12596394

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Solve the inequality |2x - 28] &gt; 32​
larisa86 [58]

Answer:

X>30

Step-by-step explanation:

Well the brackets or parethesis or absolutvalue sign thingy doens’t ,matter. Out of all the signs that won’t do anything at all.

Solve it normally

add 28 on both sides

2x>60

60/2=30

x>30

8 0
3 years ago
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What are the solutions to the following system?<br> -2 x² + y = -5<br> y=-3x²+5
Arturiano [62]

Answer:

x=\pm\sqrt{2}

Step-by-step explanation:

This system of equations is convenient, because the second equation already expresses y in terms of x. Now, you can substitute that in.

-2x^2-3x^2+5=-5

Multiplying both sides by -1 and bringing the 5 over:

2x^2+3x^2-10=0

Combining like terms and factoring out 5:

5(x^2-2)=0

Factoring:

5(x-\sqrt{2})(x+\sqrt{2})=0

Solutions: x=\pm\sqrt{2}

Hope this helps!

3 0
4 years ago
Triangle ABC is a right triangle and cos(22.6o)=StartFraction b Over 13 EndFraction. Solve for b and round to the nearest whole
Art [367]

Answer:

a = 5 and b = 12

Step-by-step explanation:

<u>Step 1: Find angle B</u>

<em>Angle C = 90°</em>

<em>Angle A = 22.6°</em>

<em>Angle B = B</em>

<em>All angles in a triangle are equal to 180°.</em>

Angle A + Angle B + Angle C = 180°

22.6 + 90 + B = 180°

B = 180 - 112.6

B = 67.4°

<u>Step 2: Find the value of side AC 'b'</u>

<em>Hypotenuse = 13</em>

<em>Adjacent = b</em>

<em>Angle A = 22.6°</em>

Cos (Angle) = Adjacent/Hypotenuse

Cos (22.6) = b/13

b = 12

<u>Step 3: Find the value of side CB 'a'</u>

<em>Hypotenuse = 13</em>

<em>Opposite = a</em>

<em>Angle A = 22.6°</em>

Sin (angle) = Opposite/Hypotenuse

Sin (22.6°) = a/13

a = 4.99 rounded off to 5

Therefore, the value of a=5 and b=12.

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8 0
4 years ago
Read 2 more answers
Help ity help ity help help help
antoniya [11.8K]

Answer:

#11

2 is best described as Term one

x is best described as the Variable

16 is best described as Term two

#12

2x10=20

Step-by-step explanation:

I am pretty sure of my answers.

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7 0
3 years ago
The following data are from an experiment designed to investigate the perception of corporate ethical values among individuals w
alukav5142 [94]

Answer:

Part 1

a. Sum of Squares, Treatment= 61

b. Sum of Squares, Error= 7.5

c. Mean Squares, Treatment = 30.5

d. Mean Squares, Error= 0.5

2. the F value lies in the rejection region > 3.6823

3. The value of the test statistic = 61

4. The p-value is < 0.00001

5. Conclusion

Since p-value < α, H0 is rejected.

6. Between x`2 and x`3

7. Fisher's Least Significant Difference value almost 0.869

8.There is a significant difference between the means

Step-by-step explanation:

Summary of Data

                       <u>   Treatments</u>

                       1             2             3                 Total

n                      6             6             6                   18

∑x                   42          57           30                  129

Mean              7            9.5           5                  7.167

<u>∑x2              298         543        152                    993</u>

<u>Sd.D       0.8944     0.5477     0.6325           2.0073</u>

ANOVA Table

<u>Source                                  SS              df                  MS </u>

Between-treatments           61              2                   30.5       F = 61

<u>Error                                     7.5           15                     0.5 </u>

<u>Total                                     6             8.5                     17 </u>

a. Sum of Squares, Treatment= 61

b. Sum of Squares, Error= 7.5

c. Mean Squares, Treatment = 30.5

d. Mean Squares, Error= 0.5

2. Using alpha= 0.05 the F value lies in the rejection region i.e F > 3.6823

x1` -x2`= 7-9.5= -2.5 Not significant as difference <3.68

x1`- x3`= 7-5= 2 Not significant as difference <3.68

x2` -x3`= 9.5-5= 4.5 Significant as difference > 3.68

3. The value of the F test statistic = 61

4. The p-value is < 0.00001

5. Conclusion

<em>Since p-value < α, H0 is rejected.</em>

6. Using alpha= .05, differences occurs between x2` and x3` as their difference is greater than 3.68

7. Fisher's Least Significant Difference value almost 0.869

Least Significant Difference= t( 0.025,15) √2s²/r s²= 0.50 r= 6 =n1=n2=n3

Least Significant Difference= 2.13 √ 2*0.50/ 6

=0.869

8.There is a significant difference between the means

x1` -x2`= 7-9.5= -2.5 Significant as difference > Least Significant Difference

x1`- x3`= 7-5= 2 Significant as difference > Least Significant Difference

x2` -x3`= 9.5-5= 4.5 Significant as difference > Least Significant Difference

6 0
3 years ago
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