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deff fn [24]
4 years ago
12

The conditional relative frequency table was generated by row using frequency table data comparing the hat size and shirt size o

f children on a baseball team. A 4-column table with 3 rows. The first column has no label with entries medium shirt, large shirt, total. The second column is labeled child-sized hat with entries almost equals 0.67, 0.2, 0.48. The third column is labeled adult-sized hat with entries almost equals 0.33, 0.8, 0.52. The fourth column is labeled total with entries 1.0, 1.0, 1.0. The coach attempts to determine an association between shirt size and hat size. Which is most likely true? An association cannot be determined because 0.48 is similar to 0.52. An association cannot be determined because the sum of each column is not 1.0. There is likely an association because 0.8 is not similar to 0.2. There is likely an association because 0.8 is not similar to 0.33.
Mathematics
2 answers:
Leya [2.2K]4 years ago
8 0

Answer:

The answer is C.

Step-by-step explanation:

Crazy boy [7]4 years ago
5 0

Answer:

There is likely an association because 0.8 is not similar to 0.33.

Step-by-step explanation:

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You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a
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Answer:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

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And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

\bar X=573 represent the sample mean

\mu population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=36-1=35

The Confidence level is 0.90 or 90%, the significance would be \alpha=0.1 and \alpha/2 =0.05, and the critical value for this case would be t_{\alpha/2}=1.690

And replacing we got:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967    

And the 90% confidence interval would be between [566.8033 and 579.1967]

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