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Ilya [14]
3 years ago
12

Color of seagrass beds on navigational charts? Please quickly

Computers and Technology
1 answer:
Nadya [2.5K]3 years ago
5 0
Hello! The color of seagrass beds on navigational charts are brown, because they are in shallow areas and it helps you know the locations of them.
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Which access control principle specifies that no unnecessary access to data exists by regulating members so they can perform onl
sdas [7]
Least privilege is the data access principle that ensures to unnecessary access to data exists by regulation members so that can perform only minimum data manipulation necessary. The principle of least privilege or as called as POLP is the run-through of controlling access to the minimal level that will permit normal functioning. The norm of least privilege interprets to giving people the lowermost level of user right that they can have and still do their jobs. The principle is also functional to things other than people as well as programs and processes. It is created in the US department of defense in the 1970’s and aimed to limit the potential damage of any security breach either accidental or malicious. 
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3 years ago
_____ CRM systems are hosted by an external vendor in the vendor's data center.
PtichkaEL [24]

Answer: On- demand

Explanation:

 On demand CRM system are basically hosted by the external vendor in the vendor data center. CRM is basically stand for customer relationship management.

CRM is a strategy that are used for managing the organisation relationship with the customers.

On demand CRM define as software availability for the customers. It basically connected with the idea of software on demand. The software are modify according to the current requirement and demand.

8 0
3 years ago
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
Given the following code: public class Test { public static void main(String[] args) { Map map = new HashMap(); map.put("123", "
Phoenix [80]

Answer:

There are no statements in the question, so I explained the whole code.

Explanation:

A map consists of key - value pairs. The put method allows you to insert values in the map. The first parameter in the put method is the key, and the second one is the value. Also, the keys must be unique.

For example, map.put("123", "John Smith");   -> key = 123, value = John Smith

Even though the key 123 is set to John Smith at the beginning, it will have the updated value Steve Yao at the end. That is because the keys are unique.

Note that the key 222 also has Steve Yao for the value, that is totally acceptable.

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3 years ago
Research the design basis threat (DBT) in terms of Cybersecurity for an organization of your choice. Discuss what the Cybersecur
tiny-mole [99]

A Design Basis Threat (DBT) is known to be a characteristics of any given or potential insider and also those of external adversaries, that may try to have or gain unauthorized removal or sabotage, against a physical protection system that was set up designed and evaluated.

<h3>What are Cybersecurity objectives?</h3>

Cybersecurity aims are:

  • To protect computer system,
  • To protect networks,
  • To protect software programs from such cyber attacks.

Note that a lot of digital attacks are targeted at accessing, changing, or deleting sensitive information as well as others.

Learn more about IT from

brainly.com/question/1276995

#SPJ1

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2 years ago
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