Answer:
Step-by-step explanation:
What variable are you solving for?
Lololololol. I long since forgot how to do this. rip
f(x)=x3−5
Replace f(x)
with y
.
y=x3−5
Interchange the variables.
x=y3−5
Solve for y
.
Since y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
y3−5=x
Add 5
to both sides of the equation.
y3=5+x
Take the cube root of both sides of the equation to eliminate the exponent on the left side.
y=3√5+x
Solve for y
and replace with f−1(x)
.
Replace the y
with f−1(x)
to show the final answer.
f−1(x)=3√5+x
Set up the composite result function.
f(g(x))
Evaluate f(g(x))
by substituting in the value of g into f
.
(3√5+x)3−5
Simplify each term.
Remove parentheses around 3√5+x
.
f(3√5+x)=3√5+x3−5
Rewrite 3√5+x3
as 5+x
.
f(3√5+x)=5+x−5
Simplify by subtracting numbers.
.
Subtract 5
from 5
.
f(3√5+x)=x+0
Add x
and 0
.
f(3√5+x)=x
Since f(g(x))=x
, f−1(x)=3√5+x is the inverse of f(x)=x3−5
.
f−1(x)=3√5+x
Answer:
The first one is your answer.
Step-by-step explanation:
What you do is you have to look at the 2/18 in the square root. That can come out to be 1/3. So you know that a 3 is going to be on the bottom.
Now you look at the x^5. What you do is you make it until you have 5 x's like this x, x, x, x, x. You then put them in pairs of two.
x,x x,x x. There are two pairs of two so that comes out.
So you have 1x^2sqrtx/3. which is the first one.
#1 is your answer.
