Question

Find the equation of the line passing through the points (6,3) and (-4,3) Y=

Answer 1

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Equation of line passing through given points :

Let's proceed with two point form ~

$\qquad \sf \dashrightarrow \: y - y1 = \cfrac{y2 - y1}{x2 - x1} (x - x1)$

Assume :

$\qquad \sf \dashrightarrow \: y - 3= \cfrac{3 - 3}{ - 4 - 6} (x - 6)$

$\qquad \sf \dashrightarrow \: y - 3= \cfrac{0}{ - 10} (x - 6)$

$\qquad \sf \dashrightarrow \: y - 3 = 0$

$\qquad \sf \dashrightarrow \: y = 3$

So, the equation of required line is : y = 3 ~