1. Many state students are looking for employment opportunities through outsourced jobs in other countries, since their possibilities have been reduced within their own country.

2.One of the independent variables is outsourced work.

a. a type of moderate independent variable.

3. The analysis of the high demand for outsourcing.

a. Control dependent variable.

4.It is an experimental design.

Because you want to see if the outsourced market really has any effect on the US economy.

6. Possible dependent variables such as the effect on the US market or the creation of new markets, I do not consider to be reliable variables to measure the cause or independent variable.

7.It is ecologically valid in the sense that it allows visualizing a positive impact on a way of working that allows reducing costs in all senses, both monetary and transportation, contributing to the care of nature.

8.I do not consider that cause and effect can be claimed.

a.While the one that exitates this type of outsourced work from many parts of the world, this does not guarantee that it is the only source of income for a person, since these outsourced jobs often represent additional income.

9. Focal groups.

7 0

3 years ago

What is the value of the 10th term in this arithmetic sequence? <br><br>2,5,8,11,...

yKpoI14uk [10]

It looks to be 29, if the rule is to add 3z

8 0

3 years ago

Find the value of x. If necessary, you may learn with the markings on a figure indicate.

love history [14]

Answer:

112

Step-by-step explanation:

6 0

3 years ago

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0

3 years ago