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USPshnik [31]
2 years ago
10

2 Find all positive and negative integers b such that x² + bx + 21 factors.

Mathematics
1 answer:
True [87]2 years ago
5 0

All the possible values of b will be ±22 and ±10. Thus, there are 4 possibilities such that x2 + bx + 21 factors.

We have been the equation as

                          x2 + bx + 21

Now all the possible factors of 21 are ±1, ±3, ±7 and ±21

We can write the linear factors as (x+)(x+) or (x-)(x-) as the coefficient of x2 is 1 .

The possible linear factors are :

(x + 1)(x + 21) = x2 + 22x + 21

(x + 3)(x + 7) = x2 + 10x +21

(x – 1)(x – 21) = x2 – 22x + 20

(x – 3)(x – 7) = x2 – 10x + 20

Hence all the possible values of b will be ±22 and ±10. There are 4 possibilities.

Learn more about  factorization here : brainly.com/question/25829061

#SPJ9

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