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Crank
1 year ago
14

The zeroes of f(x) = x3 + 3x2 + 2x are .

Mathematics
2 answers:
Vaselesa [24]1 year ago
7 0

The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2

<h3>How to determine the zeros of the function?</h3>

The function is given as:

f(x) = x^3 + 3x^2 + 2x

Factor out x in the above function

f(x) = x(x^2 + 3x + 2)

Set the function to 0

x(x^2 + 3x + 2) = 0

Factorize the expression in the bracket

x(x + 1)(x + 2) = 0

Split the expression

x = 0, x + 1 = 0 and x + 2 = 0

Solve for x

x = 0, x = -1 and x = -2

Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2

Read more about zeros of function at

brainly.com/question/20896994

#SPJ1

KatRina [158]1 year ago
4 0

Answer:

-2, -1 and 0

Step-by-step explanation:

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Express x2- 8x + 5 in the form (x -a)2-b where a and b are integers.
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(x - 4)² - 11

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x² - 8x + 5

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A. Show that the vector v = ai + bj is perpendicular to the line ax + by = c by establishing that the slope of v is the negative
pishuonlain [190]

Answer:

Part A:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector = \frac{b}{a}

Step-by-step explanation:

Condition for perpendicular is:

m_1m_2=-1

Part A:

Consider the vector v = ai + bj

x component of vector=a

y component of vector=b

Slope of vector=m_1=\frac{y}{x}=\frac{b}{a}

Consider the line ax + by = c:

Rearranging the equation:

ax+by=c

by=c-ax

y=\frac{-ax}{b}+\frac{c}{b}

According to general equation of line: y=mx+c

Where m is the slope

In our case the slope of above line is:

m_2=\frac{-a}{b}

According to the condition of perpendicular:

m_1m_2=-1

\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector is also calculated above.

Since the slope of vector is negative reciprocal of the slope of the given line:

According to equation of line ax + by = c

y=\frac{-ax}{b}+\frac{c}{b}

According to  general equation of line: y=mx+c

Where m is the slope

Slope of given line=m=\frac{-a}{b}

negative reciprocal of the slope of the given line = \frac{b}{a}

Slope of vector = \frac{b}{a}

5 0
2 years ago
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