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3 years ago

6y²×3³×18² what do I do

Mathematics

1 answer:

koban [17]3 years ago

6 0

Answer:

52488y²

Step-by-step explanation:

first solve for 3³. then solve for 18²

3³=27

18²=324

27*324=8748

then multiply 8748 by 6y²

=52488y^2

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The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$

$P(300 \leq x \leq 500) = 61.2\%$

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03$

$=P( z \leq \displaystyle\frac{x - 385}{110})=0.997$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28$

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0

3 years ago

Does this graph have any vertical asymptotes? If so, where?

tresset_1 [31]

Answer:

There are no vertical asympotes for this rational function.

Step-by-step explanation:

For rational functions, a vertical asymptote exists for every value of the independent variable such that function become undefined, that is, such that denominator is zero. Let be the following rational function:

$C(p) = \frac{25000\cdot p}{100-p}$ , $0\le p < 100$

There is a vertical asymptote for this case:

$100-p = 0$

$p = 100$

Which is out of the interval given to the rational function. Hence, we conclude that there are no vertical asympotes for this rational function.

5 0

2 years ago

40 - 2x [(8 x 3 + 6) +<br>12 -2 pls answer correctly

Degger [83]

Answer:

40 is the answer . is it right or Not?

3 0

2 years ago

Read 2 more answers

Which of the following is equivalent to (n-3)(n-5) a. n2-8n+15, b. n2+8n-15, c. n2-15n+8

solong [7]

Foil the binomials

First: n*n=n^2
Outer: n*-5=-5n
Inner: -3*n=-3n
Last: -3*-5=15

Put it together and simplify
n^2-5n-3n+15
n^2-8n+15

Final answer: A

5 0

3 years ago

Erin and her friends are taking a road trip. She has agreed to drive between hours 3 and 6 of the trip. If h represents the hour

Inessa [10]

Answer:

To the right of

To the left of

Below

(4.5,200)

Step-by-step explanation:

Got it right on Edge.

6 0

3 years ago