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2 years ago

Please answer problems 7 and 8 ASAP!

Mathematics

2 answers:

Lilit [14]2 years ago

6 0

We need to see the whole page+problem.

Dennis_Churaev [7]2 years ago

3 0

8. The answer to this is 9w but, can't see number 7 if u send a new picture I can tell you tho :)

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A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi

inessss [21]

Answer:

$\frac{1429}{120}$ or $11\frac{109}{120}$

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = $\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7$

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

$x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)$

$x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)$

$x = \frac{1}{120}(40+30+24+15+840)$

$x = \frac{1}{120}(949)$

$x = \frac{949}{120}$

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = $\frac{949}{120}+4$

Original number of peaches = $\frac{949+4\times 120}{120}$

Original number of peaches = $\frac{949+480}{120}$

Original number of peaches = $\frac{1429}{120}$

Original number of peaches = $11\frac{109}{120}$

Therefore the original number of peaches in the basket is $\frac{1429}{120}$ or $11\frac{109}{120}$

5 0

2 years ago

Plz help ASAP number 4 I️ have B and 7 I️ have c plz help with the rest

Veronika [31]

Answer:

5 is interpolation

hope this helps!

4 0

2 years ago

Use the discriminant to find the number and type of solution for x^2+6x=-9

likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

$\displaystyle \large{D = {b}^{2} - 4ac}$

First, arrange the expression or equation in ax^2+bx+c = 0.

$\displaystyle \large{ {x}^{2} + 6x = - 9}$

Add both sides by 9.

$\displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}$

Compare the coefficients so we can substitute in the formula.

$\displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }$

a = 1
b = 6
c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

$\displaystyle \large{D = {6}^{2} - 4(1)(9)} \\ \displaystyle \large{D = 36 - 36} \\ \displaystyle \large{D = 0}$

Since D = 0, the type of solution is one real root.

6 0

2 years ago

Please help .......

WITCHER [35]

f(n) = n² + 20

f(1) = 1² + 20 = 21

f(2) = 2² + 20 = 24

f(3) = 3² + 20 = 29

f(4) = 4² + 20 = 36

f(5) = 5² + 20 = 45

f(6) = 6² + 20 = 56

a) first three terms

Answer: 21, 24, 29

b) how many < 50

f(5)=45, f(6)=56 so

Answer: 5

7 0

3 years ago

Classwork/Homework:

REY [17]

An object's dimensions are: length of 25cm, wight of 10cm, and height of 15cm. calculate the object's density if its mass is 3000g

3 0

2 years ago