To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.
Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.
Combining the three, we have the overall GCF = 3m2n
D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.
C
is wrong as well. The triangles might be similar, but they are more. They are congruent.
B
You don't have to prove that. It is given on the way the diagram is marked.
A
A is your answer. The two triangles are congruent by SAS
X = 59, y = 44
2x + 18 + x - 15 = 180
3x + 3 = 180
3x = 177
x = 59
x - 15 = y
59 - 15 = y
44 = y
2^x-3
im taking this test today as well, and i have the answer to this question on the study guide so this is right.
