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Aneli [31]
3 years ago
11

3x+7=16 can someone help me solve this

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

***3x+7=16***

Subtract 7 from each side. You get 3x=9

Divide each side by 3 to isolate x. You get x=3

You can check the answer by plugging in the 3 into the original equation.

You get 3(3)+7=16; which is 9+7=16

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Y = -5 + 6 -----------
andreyandreev [35.5K]

Answer:

y = -5 + 6=1 is your answer

6 0
3 years ago
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I'd Point A is located at (9,2) on a coordinate plane and point B is located at (-9,10), what is the distance between the two po
Fiesta28 [93]
Draw the triangle and then use Pythagoras' theorem

distance = \sqrt{18 ^{2} +8 ^{2}   }
              = 19.70 (2dp) 
4 0
3 years ago
Marisol is making a rectangular wooden frame. She wants the length of the frame to be no more than 12 inches. She has less than
evablogger [386]
<span>l ≤ 12
2l + 2w < 30 
the second and fourth option are saying she can make the length longer than twelve and the third option forgets to double the length and width so it is accurate. The first option is the right answer.</span>
6 0
3 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
What is the answer to the following: (reference the photo for answer)
Artyom0805 [142]

Answer:

9

Step-by-step explanation:

To calculate c from the first right angle triangle,

C2 = 36 + 16

C = sqrt(52)

To calculate a from the bigger right angle triangle,

B2 + 52 = (a + 4)2

B2 - a2 = -36 + 8a

A2 + 36 = B2

Solving both by elimination,

A = 72/8

=9

5 0
3 years ago
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