Volume of H₂O produced = (1.8 g) × (1 cm³/g) = 1.8 cm³
Simplifying :
Molar volume of O₂ at STP = 22400 cm³/mol
No. of moles of O₂ liberated = (1120 cm³) / (22400 cm³/mol) = 0.05 mol
According to the given equation, mole ratio H₂O : O₂ = 2 : 1
No. of moles of H₂O produced = (0.05 mol) × 2 = 0.1 mol
Molar mass of H₂O = (1×2 + 16) g/mol = 18 g/mol
Mass of H₂O produced = (0.1 mol) × (18 g/mol) = 1.8 g
Volume of H₂O produced = (1.8 g) × (1 cm³/g) = 1.8 cm³
What happens in the decomposition of hydrogen peroxide?
The decomposition of hydrogen peroxide can be summarized by the chemical equation: which states that two molecules of hydrogen peroxide break down to form two molecules of water and one molecule of oxygen gas, along with heat energy.
Why does hydrogen peroxide decompose quickly?
In many living organisms hydrogen peroxide is a product of metabolism that must be broken down, since in appreciable concentrations it is toxic. The rate of decomposition is increased by the intra-cellular enzyme catalase.
At what temperature does hydrogen peroxide decompose?
Properties. The boiling point of H 2O 2 has been extrapolated as being 150.2 °C (302.4 °F), approximately 50 °C (90 °F) higher than water. In practice, hydrogen peroxide will undergo potentially explosive thermal decomposition if heated to this temperature
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