The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻.
<h3>What are redox equations?</h3>
Redox equations are equations in which oxidation and reduction reactions occur together.
Redox reactions can take place in alkaline or acidic mediums.
The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻
In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.
Learn more about redox equations at: brainly.com/question/27239694
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no of moles in 4 grams of H2=4/2=2
2H2+O2............2H2O
the reaction shows that 2 moles of H2 react with 1 mole of O2 to produced 2 moles H2O
now no of moles in 36grams of H2O=36/18=2
therefore he needed 1 mole of O2 to produce 36 grams of H2O and 1 mole of oxygen is equal to 32 grams of O2
Flashlight or smoke detector have simple dry cell or batteries.
The cell are generally of 6 volts.
In these cells Zn acts as anode and graphite electrode acts as cathode.
A mixture of MnO2 and carbon blacks surrounds the graphite cathode
The electrolyte is ZnCl2 and ammonium chloride. This mixture is used as thick paste.
C is the correct answer. Double displacement reaction, also called as metathesis, is a type of reaction wherein two compounds react to form new compounds. This case the cations and the anions of the reactants replace each other forming the new compounds.
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).
We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).
First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/
1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.
Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.
The final answer is </span>(2) 20.0 mL.<span>
Also, this problem can also be done by using
dimensional analysis.
Hope this would help~
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