The area of a square increases by a factor 2n when its perimeter increases by a factor of n
<h3>How to determine the perimeter and area of each square?</h3>
Start by calculating the side length of each square
From the diagram, we have the following side lengths in ascending order
Square 1 = 2
Square 2 = 4
Square 3 = 8
<u>The perimeter</u>
This is calculated as:
P = 4 * Side length
So, we have:
Perimeter Square 1 = 4 * 2 = 8
Perimeter Square 2 = 4 * 4 = 16
Perimeter Square 3 = 4 * 8 = 32
Hence, the perimeters of the squares are 8, 16 and 32
<u>The area</u>
This is calculated as:
A = Side length^2
So, we have:
Area Square 1 = 2^2 = 4
Area Square 2 = 4^2 = 16
Area Square 3 = 8^2 = 64
Hence, the areas of the squares are 4, 16 and 64
<h3>What happens to the area of a square when its perimeter increases by a factor of n?</h3>
Using the computations in (a), the area of a square increases by a factor 2n when its perimeter increases by a factor of n
Read more about area and perimeter at:
brainly.com/question/24571594
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