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nekit [7.7K]
3 years ago
9

How many reasons must your thesis contain and which reason is first

Mathematics
1 answer:
finlep [7]3 years ago
5 0
<span><span>The more sources the better
Every researcher aims to have a standardized and uniform study when a study will be replicated or repeated for various reasons.

</span>The number of accounts and evidential support of your thesis must be consistent and be sufficient and succinct to the topic of study. These reasons and evidential support should claim proximate with the pronounced experimentation and variables which will be studied. In sense, the more accounts and sources the better is your study, the greater it will stand out and present itself. This is important for every thesis paper or dissertation since these accounts provides and explicitly discusses the studies that have been undertaken before which can greatly influence the current study's credibility and reliability. </span>

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How do I solve for x?
zheka24 [161]
3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15
3 0
3 years ago
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Data from the Centers for Medicare and Medicaid Services indicates that the annual per capita out-of-pocket expenses for health
Talja [164]

Answer:

During the year 2021.

Step-by-step explanation:

As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.

Knowing that, <u>we clear x</u> (<em>this is the number of years past the year 2000, so it will contain our desired information</em>).

y=39.6x+543\Leftrightarrow x=\frac{y-543}{39.6}

Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and <em>this total is our variable y</em>, then

x=\frac{1400-543}{39.6}\approx 21.6

Finally, we know that <u>x is the number of years past the year 2000</u>, so the answer is that during the year 2021, <em>the per capita out-of-pocket expenses for health care are predicted to be $1400</em>.

3 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
A triangle has the vertices A(-7, 8), B(1, -7), and C(7,6). After a dilation, the vertices of the image are A(-28, 32).
steposvetlana [31]

Answer: the answer is A.4

Step-by-step explanation:

Dilation in this context is the transformation is an object into a larger one.

ABC is transformed to A'B'C'

To get the scale factor, we divide the coordinates of A'B'C' by ABC

i.e

A'/A = -28/-7, 32/8 = 4

Or

B'/B = 4/1, -28/-7 = 4

Or

C'/C = 28/7, 24/6 = 4

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br>Which expression is equal to 5/13√ ?
Anvisha [2.4K]

\dfrac{5}{\sqrt{13}}\cdot\dfrac{\sqrt{13}}{\sqrt{13}}=\dfrac{5\sqrt{13}}{13}

\text{Used:}\ \sqrt{a}\cdot\sqrt{a}=a

7 0
3 years ago
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