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2 years ago

H(t) = −t2 + t + 1 h(−1)

Mathematics

1 answer:

Gwar [14]2 years ago

6 0

Based on the given parameters, the value of the function h(-1) is -1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(-1)

This means that t = -1

So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1

h(-1) =-(-1)^2 + (-1) + 1

Evaluate the exponent

h(-1) =-1 - 1 + 1

Evaluate the like terms

h(-1) = -1

Hence, the value of the function h(-1) is -1

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densk [106]

Answer:

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14. y = 1/2x - 2

Step-by-step explanation:

You want to put y on one side and the rest of the numbers on the other side. You can do this by adding or subtracting or dividing the numbers/variables on the left.

13.

4x + y = 6

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or rewritten as:

y = -4x + 6

14.

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3 years ago

Please solve this equation and show work please tysm 3(g−7)=2(10+g)

riadik2000 [5.3K]

Answer:

g=41

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(g−7)=2(10+g)

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Step 2: Subtract 2g from both sides.

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8 0

3 years ago

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stiks02 [169]

Answer 4

Explain
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3 years ago

Find a homogeneous linear differential equation with constant coefficients whose general solution is given by

frez [133]

Answer:

$y" + 2y' + 2y = 0$

Step-by-step explanation:

Given

$y=c_1e^{-x}cosx+c_2e^{-x}sinx$

Required

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Rewrite the expression as:

$y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)$

Where

$\alpha = -1$ and $\beta = 1$

For a homogeneous linear differential equation, the repeated value m is given as:

$m = \alpha \± \beta i$

Substitute values for $\alpha$ and $\beta$

$m = -1 \± 1*i$

$m = -1 \± i$

Add 1 to both sides

$m +1= 1 -1 \± i$

$m +1= \± i$

Square both sides

$(m +1)^2= (\± i)^2$

$m^2 + m + m + 1 = i^2$

$m^2 + 2m + 1 = i^2$

In complex numbers:

$i^2 = -1$

So, the expression becomes:

$m^2 + 2m + 1 = -1$

Add 1 to both sides

$m^2 + 2m + 1 +1= -1+1$

$m^2 + 2m + 2= 0$

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6 0

3 years ago

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maks197457 [2]

Correct answer is
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4 years ago