Question

H(t) = −t2 + t + 1 h(−1)

Answer 1

Based on the given parameters, the value of the function h(-1) is -1

How to evaluate the function?

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(-1)

This means that t = -1

So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1

h(-1) =-(-1)^2 + (-1) + 1

Evaluate the exponent

h(-1) =-1 - 1 + 1

Evaluate the like terms

h(-1) = -1

Hence, the value of the function h(-1) is -1

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Complete question

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(−1)