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Darya [45]
2 years ago
12

H(t) = −t2 + t + 1 h(−1)

Mathematics
1 answer:
Gwar [14]2 years ago
6 0

Based on the given parameters, the value of the function h(-1) is -1

<h3>How to evaluate the function?</h3>

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(-1)

This means that t = -1

So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1

h(-1) =-(-1)^2 + (-1) + 1

Evaluate the exponent

h(-1) =-1 - 1 + 1

Evaluate the like terms

h(-1) = -1

Hence, the value of the function h(-1) is -1

Read more about functions at:

brainly.com/question/1415456

#SPJ1

<u>Complete question</u>

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(−1)

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Step-by-step explanation:

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3.- Multiply the result (2x²) by the second term of the divisor and place the result below the like term.

4.- Add the results.

5.- Continue with this process until the remainder be lower than the divisor.

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