Answer:
- <u><em>Sometimes.</em></u>
Explanation:
The statement is <em>P forward Q is true and q is true, then p is true sometimes always or never.</em>
<em />
That, written using logical symbology, is:
- p → q,
- q is true
- then p is ?
p → q is known as a conditional statement.
When the conditional p → q is true and p is also verified to be true, you must conclude that q is (necessarily) true (else the conditional would be false).
That also means that if q is verified to be false (not true), p must necessarily be false (else the conditional would be false).
Nevertheless, the fact that q is true, does not permit to conclude whether p is true or false: p can be either true or false when you only know that q is true.
Then, you cannot tell that p is true always or never; some times it could be true and others false.
∠1 and ∠2 are complementary.
∠1 + ∠2 = 90°
Question a:
∠1 = 23°
∠2 = 90 - 23 = 67°
Ans: 67°
Question b:
∠1 = x
∠2 = 2x + 3
x + 2x + 3 = 90
3x + 3 = 90
3x = 90 - 3
3x = 87
x = 29
∠1 = 29°
∠2 = 2(29) + 3 = 61°
Ans: ∠1 = 29°, ∠2 = 61°
<h2>
Explanation:</h2><h2>
</h2>
As I understand the question you have the following expressions given in scientific notation:
<u>Expression A:</u>
<u></u>
<u></u><u></u>
<u></u>
<u>Expression B:</u>
<u></u>
<u></u><u></u>
<u></u>
So we need to compare both expression in order to know how much times is expression A bigger than B. So:
In conclusion is times as much as
Answer:
<h2>The determinant is 1</h2>
Step-by-step explanation:
Given the 3* 3 matrices , to compute the determinant using the first row means using the row values [0 4 1 ] to compute the determinant. Note that the signs on the values on the first row are +0, -4 and +1
Calculating the determinant;
The determinant is 1 using the first row as co-factor
Similarly, using the second column as the cofactor, the determinant will be expressed as shown;
Note that the signs on the values are -4, +(-3) and -3.
Calculating the determinant;
The determinant is also 1 using the second column as co factor.
<em>It can be concluded that the same value of the determinant will be arrived at no matter the cofactor we choose to use. </em>
We can determine the correct graph by finding its roots
x² - 4x - 12 = 0
x² - 6x + 2x - 12 = 0
x(x-6) +2(x-6) = 0
(x+2)(x-6) = 0
This means the roots of the function are x=-2, and x=6 and the graph will cross x axis at these two points. From the given graphs, the graph B seems to cross these points.
So the answer to this question is option B