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dybincka [34]
2 years ago
15

I dont understand this 8x5/14=

Mathematics
2 answers:
adoni [48]2 years ago
7 0

Answer:

8x5/14=

this means 8x5/14=10

max2010maxim [7]2 years ago
6 0
The answer will be 10
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How do you solve this one step equation that looks like n-6=-9 with work
iogann1982 [59]

Answer:

n= -3

Step-by-step explanation:

n-6= -9

 +6 +6

   n= -3

7 0
3 years ago
Which two numbers have a sum of 15 and a product of 36
kap26 [50]

Answer:  3  and  12

<u>Step-by-step explanation:</u>

Let x represent one of the numbers and y represent the other number. Then,

Sum:      x + y = 15      →    y = 15 - x

Product: xy  = 36


Use substitution method by replacing "y" with "15 - x" in the second equation, then solve for x:

x(15 - x) = 36

15x - x² = 36

       0  =  x² - 15x + 36

       0  =  (x - 3)(x - 12)

 0 = x - 3     and       0 = x - 12

 x  = 3                       x = 12

5 0
3 years ago
Don't you times by a thousand then times the answer<br> I got 60,000
Firdavs [7]

Answer:

i think that's right

Step-by-step explanation:

7 0
3 years ago
Please solve this question.​
Anon25 [30]

\left(\dfrac{1}{1+2i}+\dfrac{3}{1-i}\right)\left(\dfrac{3-2i}{1+3i}\right)=\\\\\left(\dfrac{1-2i}{(1+2i)(1-2i)}+\dfrac{3(1+i)}{(1-i)(1+i)}\right)\left(\dfrac{(3-2i)(1-3i)}{(1+3i)(1-3i)}\right)=\\\\\left(\dfrac{1-2i}{1+4}+\dfrac{3+3i}{1+1}\right)\left(\dfrac{3-9i-2i-6}{1+9}\right)=\\\\\left(\dfrac{1-2i}{5}+\dfrac{3+3i}{2}\right)\left(\dfrac{-3-11i}{10}\right)=\\\\\left(\dfrac{2(1-2i)}{10}+\dfrac{5(3+3i)}{10}\right)\left(\dfrac{-3-11i}{10}\right)=

\dfrac{2-4i+15+15i}{10}\cdot\dfrac{-3-11i}{10}=\\\\\dfrac{17+11i}{10}\cdot\dfrac{-3-11i}{10}=\\\\\dfrac{-51-187i-33i+121}{100}=\\\\\dfrac{70-220i}{100}=\\\\\dfrac{70}{100}-\dfrac{220i}{100}=\\\\\boxed{\dfrac{7}{10}-\dfrac{11}{5}i}

8 0
3 years ago
Given right triangle ABC, what is the value of tan(A)? Five-thirteenths Twelve-thirteenths Twelve-fifths Thirteen-twelfths
WITCHER [35]

Answer:

Twelve-fifths.

Step-by-step explanation:

The diagram is shown below

Given triangle be right angled at B,

Withe reference to \angle A,

Its opposite side is BC=12 , adjacent side is AB=5 and hypotenuse is AC=13

We are to find the value of tan(A)

We know tan=\frac{opposite}{adjacent}

Substituting the above values we get,

tan(A)= \frac{BC}{AB}=\frac{12}{5}

So the answer is Twelve-fifths.

8 0
3 years ago
Read 2 more answers
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