Hello :
<span>g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
Answer: Option D.
Step-by-step explanation:
To solve this exercise you must keep on mind the Angle at the Center Theorem.
According to the Angle at the Center Theorem, an inscribed angle is half of the central angle.
Therefore, given in the inscribed angle m∠BAC=35°, you can calculate the central angle m∠EFD as following:
- Solve for EFD.
- When you substitute values. you obtain:
Answer:
x = 0
y = -12
Step-by-step explanation:
Plug in what y is equal to into the second equation
-3(x - 12) = 2x + 36
Distribute the -3
-3x + 36 = 2x + 36
-36 -36
-3x = 2x
They cannot be equal so x = 0
Plug in 0 into the y equation
y = 0 - 12
y = -12
The perpendicular line will have a slope of b/a.
To find this, we first have to solve our equation for slope intercept form.
ax + by = c ----> subtract ax
by = -ax + c ----> divide by b
y = -a/bx + c/b.
So we know the slope of this equation to be -a/b. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of b/a.
Replace the 'x' in the formula for g(x) by f(x):-
g(f(x)) = (x-7)^3
Its D
