Given triangle ABC with coordinates A(−5, 4), B(−5, 1), and C(−7, 0), and its image A′B′C′ with A′(−1, 0), B′(−4, 0), and C′(−5,
UNO [17]
Answer:
y = x+5
Step-by-step explanation:
A graph can help.
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The line of reflection will pass through the midpoints of AA' and BB'.
The midpoint of AA' is ((-5, 4) +(-1, 0))/2 = (-3, 2)
The midpoint of BB' is ((-5, 1) +(-4, 0))/2 = (-4.5, 0.5)
The slope of the line through these points is ...
Δy/Δx = (2 -0.5)/(-3-(-4.5)) = 1.5/1.5 = 1
Then the y-intercept can be found from
y = x + b
2 = -3 + b
5 = b
So, the line of reflection is ...
y = x + 5
Answer:
180.82
Step-by-step explanation:
750,000 x .022=16,500 per year
16,500/365 days =45.2055/day
45.2055 x 4 days = 180.82
Answer:
3621
x 4
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14,484
Step-by-step explanation:
The reflection of the original triangle is option C
Answer:
Step-by-step explanation:
1) AC⊥BD and BD bisects AC 1) given
2) AD≅DC 2) linear bisector thm.
3) ∠ADB and ∠CDB are right angles 3) perpendicular bisector thm.
4) ∠ADB ≅ ∠CDB 4) all right ∡'s are congruent
5) BD ≅ BD 5) reflexive POV
6) ΔABD ≅ ΔCBD 6) SAS
Hope this helps!
btw, I was not able to put the lines on top of some of the letters, so my apologies.