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3 years ago

6

Fifteen percent of the students at Central High take Spanish, 12% take French, and 4% take both. If a student is selected at ran

dom, what is the
probability that the student takes Spanish or French?
A 31%
B.27%
C. 23%
D. 19%

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

C. 23%

Step-by-step explanation:

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John grew 36 plants with 12 seed packets. With 15 seed packets, how many total plants can John have in his backyard?

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There are 75 balloons in each package. How many balloons are in 20 packages?

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4 years ago

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

==================================================

Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

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4 years ago

Evaluate \dfrac n6+2

vagabundo [1.1K]

<h2>Explanation:</h2><h2></h2>

Here we have the following expression:

$\frac{n}{6}+2 \\ \\ \\ When: \\ \\ n=12$

What we need to do is to substitute $n=12$ into our expression. Therefore:

$\frac{n}{6}+2 \\ \\ \frac{n}{6}+2 =\frac{12}{6}+2 =2+2=4$

Finally, when evaluating $n=12$ into the expression the result is 4.

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3 years ago

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