Answer:
B
Explanation:
B is a personal factor of resilience
1.) In 4 Copper atoms, you will have 116 electrons.
2.) You can make 3 Copper atoms out of 87 protons.
Answer: Ben Franklin
Explanation: Hope this helps! :)
Answer:
Mass of C₂H₄N₂ produced = 3.64 g
Explanation:
The balanced chemical equation for the reaction is given below:
3CH₄ (g) + 5CO₂ (g) + 8NH₃ (g) → 4C₂H₄N₂ (g) + 10H₂O (g)
From the equation, 3 moles of CH₄ reacts with 5 moles of CO₂ and 8 moles of NH₃ to produce 4 moles of C₂H₄N₂ and 10 moles of H₂O
Molar masses of the compounds are given below below:
CH₄ = 16 g/mol; CO₂ = 44 g/mol; NH3 = 17 g/mol; C₂H₄N₂ = 56 g/mol; H₂O g/mol
Comparing the mole ratios of the reacting masses;
CH₄ = 1.65/16 = 0.103
CO₂ = 13.5/44 = 0.307
NH₃ = 2.21/17 = 0.130
converting to whole number ratios by dividing with the smallest ratio
CH₄ = 0.103/0.103 = 1
CO₂ = 0.307/0.103 = 3
NH₃ = 0.130/0.103 = 1.3
Multiplying through with 5
CH₄ = 1 × 5 = 5
CO₂ = 3 × 5 = 15
NH₃ = 1.3 × 5 = 6.5
Therefore, the limiting reactant is NH₃
8 × 17 g (136 g) of NH₃ reacts to produce 4 × 56 g (224 g) of C₂H₄N₂
Therefore, 2.21 g of NH₃ will produce (2.21 × 224)/136 g of C₂H₄N₂ = 3.64 g of C₂H₄N₂
Mass of C₂H₄N₂ produced = 3.64 g
Answer:
0th order with respect to oxygen.
Explanation:
Whenever we have a table with the molarity of a substance against time, the best idea is to input the time into one cell of Excel and molarity into the other adjacent cell of Excel.
We wish to produce 3 plots: plot 1 would contain time on the x-axis and molarity values on the y-axis. In case we get a straight line in the graph, we can verify that this is a 0th order reaction.
Plot 2 would need us to calculate the natural logarithm of each concentration and plot time on the x-axis and ln of each molarity on the y-axis. In case we get a straight line, we can verify a 1st order reaction.
Plot 3 would require calculating the reciprocal of each molarity, that is, 1/[O2] in each case. Plotting time on the x-axis and 1/[O2] on the y-axis would yield a graph. In case this graph is linear, then the reaction order is 2nd.
We plot each graph and add trendline in Excel. None of the graphs is perfectly linear, so the only data we can rely on is the R-squared coefficient. The closer it is to 0, the closer your points resemble a line. Out of all three graphs, the highest R-squared value is seen for the 0th order rate law at a value of 0.8721 against 0.7749 for the 1st and 0.6255 for the second.
You may wish to refer to the Excel file for the details.