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QveST [7]
4 years ago
8

Help Me PLEASE!!!! The Struggle Is Real Right Now

Chemistry
2 answers:
dybincka [34]4 years ago
8 0

Can anyone help me with this one too?!

Anettt [7]4 years ago
3 0
PM me, I am working on the same thing!!! 

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A gas with a volume of 535 mL at a temperature of -25C is heated to 175C. What is the new volume of the gas if pressure and numb
MakcuM [25]

Answer:966.45ml

Explanation:

Using Charles law.. V1/T1=V2/T2

V1=535ml

T1=-25+273

=248k

T2= 175+273=448k

V2=?

V2= V1*T2/T1

V2=535*448/248

V2=239680/248

V2=966.45ml

5 0
4 years ago
Read 2 more answers
How to make 100 ml of 0.001 mM solution with 0.0405mM solution?
alexgriva [62]

Answer:

Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water

Explanation:

To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:

Molarity of stock (M₁) = 0.0405 mM

Volume of diluted (V₂) = 100 mL

Molarity of diluted solution (M₂) = 0.001 mM

Volume of stock solution needed (V₁) =?

M₁V₁ = M₂V₂

0.0405 × V₁ = 0.001 × 100

0.0405 × V₁ = 0.1

Divide both side by 0.0405

V₁ = 0.1 / 0.0405

V₁ = 2.47 mL

Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.

3 0
3 years ago
Lichens are an example of a(n)
Marta_Voda [28]
Lichens are an examples of Symbiosis
3 0
3 years ago
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A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced? 0.538 mol, O2 1.86 mol,
zlopas [31]

Answer:

O 2  has a mass of 1.78g

Explanation:

We are at STP and that means we have to use the ideal gas law equation!

P represents pressure (could have units of atm, depending on the units of the universal gas constant)

V represents volume (must have units of liters)

n represents the number of moles

R is the universal gas constant (has units of  

L

× a t m

m o l

×

K

)

T represents the temperature, which must be in Kelvins.

Next, list your known and unknown variables. Our only unknown is the number of moles of  

O

2

(

g

)

. Our known variables are P,V,R, and T.

At STP, the temperature is 273K and the pressure is 1 atm. The proportionality constant, R, is equal to 0.0821  

L

×

a

t

m

m

o

l

×

K

Now we have to rearrange the equation to solve for n

n

=

P

V

R

T

n

=

1

atm

×

1.25

L

0.0821

Lxxatm

m

o

l

×

K

×

273

K

n

=

0.05577

m

o

l

To get the mass of  

O

2

, we just have to use the molar mass of oxygen as a conversion factor:

0.0577

mol

O

2

×

32.00

g

1

mol

= 1.78g  

O

2

3 0
3 years ago
Read 2 more answers
What is true of a covalent bond? (03.03)
garri49 [273]

Answer:

I think B..

Explanation:

It is the sharing of electrons from one atom to another .

6 0
3 years ago
Read 2 more answers
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