Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Answer:
<h2>6.91 </h2>
Explanation:
To find the pH we must first find the pOH
The pOH can be found by using the formula
pOH = - log [ {OH}^{-} ]
We have
pOH = 7.09
Next we use the equation
pH = 14 - pOH
We have
pH = 14 - 7.09
We have the final answer as
<h3>6.91</h3>
Hope this helps you
Molarity: M = #moles of solute / liters of solution
# moles = mass / molar mass
Molar mass calculation
Barium hydroxide = Ba (OH)2
Atomic masses
Ba = 137.4 g/mol
O=16 g/mol
H=1 g/mol
Molar mass of Ba (OH)2 = 137.4 g/mol + 2*16g/mol + 2*1 g/mol = 171.4 g/mol
# mol = 25.0g/171.4 g/mol = 0.146 mol
For the volume of water use the fact that the density is 1g/ml., so 120 g = 120 ml = 0,120 liters.
M = 0.146mol / 0.120 liters = 1.22 mol/liter
The daughter isotope has an atomic number one less than the parent and a mass number two less. : A. : 1 20) The half-life<span> of </span>carbon-14<span> is about </span>6000 years<span>. </span>Assume<span> that a </span>sample<span> of </span>charcoal formed<span> by</span>burning<span> of </span>living wood 15,000 years ago<span>. How </span>much<span> of the </span>original carbon-14 would remain today? A) more than one-<span>half</span>
