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just olya [345]
2 years ago
7

14. Team 8A is selling snacks at the football game to raise money for a field trip. They are selling popcorn for $2.50 and pretz

els for $2. They have raised a total of $280 and have of 130 items. How many of each item did they sold a total sell?​
Mathematics
2 answers:
nadezda [96]2 years ago
7 0

Answer:

<u>90 pretzels and 40 popcorn.</u>

Step-by-step explanation:

This problem can be solved using a linear equation system.

Let's give each product a varaible:

x= popcorn.

y= pretzels.

Now, let's set up the equation system:

1. x+y=130

(Means that they have sold a total of 130 items of both products combined).

2. 2.5x+2y= 280

Now, let's solve the equation system through the <u>substitution method</u>.

Take one of the equations and extract a value of one of the variables:

From equation 1, solving for x, x=130-y.

Now, use that expressión and substitute it by x in equation 2:

2.5(130-y)+2y= 280

Now, let's find the value of y.

2.5(130-y)+2y= 280

325-2.5y+2y=280

-2.5y+2y=280-325

-0.5y= -45

y= -45/-0.5

<u>y= 90</u>

Now, use that value of y in equation 1 to find the value of x:

x+(90)=130

x=130-90

<u>x=40</u>

We have that y= 90 and x=40, translated to textual language, Pretzels=90 and Popcorn= 40.

Mamont248 [21]2 years ago
5 0

Answer:

  • 40 popcorns and 90 pretzels sold.

============

Let the number of popcorns is x and pretzels is y.

Set up equations:

  • x + y = 130
  • 2.5x + 2y = 280

Solve by elimination, multiply the first equation by 2 and subtract from the second equation:

  • 2.5x + 2y - 2x - 2y = 280 - 2*130
  • 0.5x = 280 - 260
  • 0.5x = 20
  • x = 20/0.5
  • x = 40

Find y:

  • 40 + y = 130
  • y = 130 - 40
  • y = 90

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Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
5x + 2y + -6x + -1z = 6x + -6x + 4y

Reorder the terms:
5x + -6x + 2y + -1z = 6x + -6x + 4y

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Add '-2y' to each side of the equation.
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Divide each side by '-1'.
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Simplifying
x = -2y + -1z
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