Question

14. Team 8A is selling snacks at the football game to raise money for a field trip. They are selling popcorn for $2.50 and pretzels for $2. They have raised a total of $280 and have of 130 items. How many of each item did they sold a total sell?​

Answer 1

Answer:

90 pretzels and 40 popcorn.

Step-by-step explanation:

This problem can be solved using a linear equation system.

Let's give each product a varaible:

x= popcorn.

y= pretzels.

Now, let's set up the equation system:

1. x+y=130

(Means that they have sold a total of 130 items of both products combined).

2. 2.5x+2y= 280

Now, let's solve the equation system through the substitution method.

Take one of the equations and extract a value of one of the variables:

From equation 1, solving for x, x=130-y.

Now, use that expressión and substitute it by x in equation 2:

2.5(130-y)+2y= 280

Now, let's find the value of y.

2.5(130-y)+2y= 280

325-2.5y+2y=280

-2.5y+2y=280-325

-0.5y= -45

y= -45/-0.5

y= 90

Now, use that value of y in equation 1 to find the value of x:

x+(90)=130

x=130-90

x=40

We have that y= 90 and x=40, translated to textual language, Pretzels=90 and Popcorn= 40.

Answer 2

Answer:

• 40 popcorns and 90 pretzels sold.

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Let the number of popcorns is x and pretzels is y.

Set up equations:

• x + y = 130
• 2.5x + 2y = 280

Solve by elimination, multiply the first equation by 2 and subtract from the second equation:

• 2.5x + 2y - 2x - 2y = 280 - 2*130
• 0.5x = 280 - 260
• 0.5x = 20
• x = 20/0.5
• x = 40

Find y:

• 40 + y = 130
• y = 130 - 40
• y = 90