Answer:
Note: The full question is attached as picture below
a) Hо : p = 0.71
Ha : p ≠ 0.71
<em>p </em>= x / n
<em>p </em>= 91/110
<em>p </em>= 0.83.
1 - Pо = 1 - 0.71 = 0.29.
b) Test statistic = z
= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]
= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]
= 0.12 / 0.043265
= 2.77360453
Test statistic = 2.77
c) P-value
P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028
P-value = 0.0056
∝ = 0.01
P-value < ∝
Reject the null hypothesis. There is sufficient evidence to support the researchers claim at the 1% significance level.
Answer:
C
Step-by-step explanation:

I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.
YESn Okau bye him yea oasis
I will give an instance to answer this. Suppose that we have 1,000 days. And it was given above that machine A has 10 % chances to malfunctioned and B has a 7%. So machine A has 100 days that malfunctioned while machine B has 70 days. And 7 days that both machines malfunctioned (10%x7%). Next is to add 100 days from machine A and 70 days from machine B and subtract with the 7 days where both of them malfunctioned. So the result is 163 days out of 1000 that we expect an incidence of failure. So the chance of machine B to malfunctioned is 70 days. 70/163 is 42.93%