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2 years ago

Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)

Mathematics

1 answer:

gavmur [86]2 years ago

8 0

The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

<h3>Polar form of a rectangular coordinate</h3>

The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)

Given the coordinate (-2√3 , 2)

r = √(-2√3)²+2²

r = √12+4

r = 4

theta = tan^-1(-2/2√3)

theta = tan^-1(-1/√3)

theta = -30 degrees = 210 degrees

The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

Learn more on polar coordinate here: brainly.com/question/14965899

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Answer:

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Step-by-step explanation:

Given

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Required

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$\frac{V}{r} = \frac{28}{h}$

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From the question, we were given that the height of the cylinder and the sphere have equal value;

This implies that the height of the cylinder equals the diameter of the sphere. In other words

$h = D$ , where D represents diameter of the sphere

Recall that $D = 2r$

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$V = \frac{28}{2}$

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