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Mandarinka [93]
2 years ago
13

Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)

Mathematics
1 answer:
gavmur [86]2 years ago
8 0

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

<h3>Polar form of a rectangular coordinate</h3>

The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)

Given the coordinate (-2√3 , 2)

r = √(-2√3)²+2²

r = √12+4

r = 4

theta = tan^-1(-2/2√3)

theta = tan^-1(-1/√3)

theta = -30 degrees = 210 degrees

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

Learn more on polar coordinate here: brainly.com/question/14965899

#SPJ1

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Pls help me !! will mark brainliest... i just need you to solve for m&lt;1 and m&lt;7 !! thanks !!
frez [133]

Step-by-step explanation:

=( n-2)180

= ( 4 - 2 )180

= 360

So, 144 + 90 + m<2 +m<1 = 360

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m<1 = 41

their is an unknown angle so let's call it x

let's find x first ( m<6=49)

x + m<6 = 180

x + 49 = 180

x = 180 - 49

x = 131

Now let's find m<7

m<7 + 38 + m<4 + x = 360

m<7 + 38 + 85 + 131 = 360

m<7 + 254 = 360

m<7 = 360 - 254

m< 7 = 106

8 0
3 years ago
Q14
posledela

Answer:

42.6cm

Step-by-step explanation:

The sum total of all the sides of the shape is the perimeter of the shape. Hence;

Perimeter = x+3 + 4 + x+9 + 2x+5

Perimeter = 4x + 21

Given

Area of the figure = 75cm^2

Area = (x+3)(2x+5) + (2x+1)(6)

75 = 2x²+5x+6x+15+12x+6

75 =  2x²+23x+21

2x²+23x+21-75 = 0

2x²+23x-54 = 0

x = -23±√23²-4(2)(-75)/4

x = -23±√529+600/4

x = -12±√1129/4

x = -12+33.6/4

x = 21.6/4

x = 5.4

Recall that;

Perimeter = 4x+21

Perimeter = 4(5.4) + 21

Perimeter = 21.6+21

Perimeter = 42.6cm

Hence the perimeter is 42.6cm

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