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kap26 [50]
3 years ago
13

Assume that the sales of a certain appliance dealer are approximated by a linear function. Suppose that sales were $14,500 in 19

82 and $65,500 in 1987. Let x = 0 represent 1982. Find the equation giving yearly sales S
Mathematics
1 answer:
Korolek [52]3 years ago
6 0
A linear function has the form : f(x)=ax+b

we are given that 

f(0)=a*0+b=b is <span>$14,500.

so the sales in the first year were </span>$14,500.

f(1) gives the sales in the second year     (year 83)
f(2) gives the sales in the third year          (year 84)
.
.
f(5) gives the sales in the sixths year        (year 87)


the slope of the line, a, is given by : 

\frac{f(5)-f(0)}{5-0}= \frac{65,500-14,500}{5}= 10,200

thus,

S=ax+b=10,200x+<span>14,500
</span>

Answer: S=10,200x+14,500  
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Answer:

d.

Step-by-step explanation:

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2 years ago
Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 (
Sonja [21]

Answer:

a) Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

\bar X = 41.538

s = 5.317

b) 44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

\bar X = 43.615

s= 5.583

c) 3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

\bar X= 3.462

s = 0.443

d) As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3.462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

Step-by-step explanation:

For this case we can use the following formulas for the mean and standard deviation:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Part a

Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

And if we calculate the mean we got:

\bar X = 41.538

s = 5.317

Part b

For this case we know that each value present a 5% of rise so we just need to multiply each value bu 1.05 and we have this new dataset:

44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

And if we calculate the new mean and deviation we got:

\bar X = 43.615

s= 5.583

Part c

The new dataset would be each value divided by 12 so we have:

3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

And the new mean and deviation would be:

\bar X= 3.462

s = 0.443

Part d

As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3,462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

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3 years ago
What is the solution to the system of equations y = -x - 5 and y = 2x + 4
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Answer:

(-3,-2)

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y = -x - 5

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x= -3

plug in x to one of the y equations

y= -(-3) -5

y=3-5

y= -2

x= -3, y= -2

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Aneli [31]

Answer:

I think your answer is 10

Step-by-step explanation:

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3 years ago
I WILL GIVE YOU A BRILLIANT
Arada [10]

Answer:

270

Step-by-step explanation:

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