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3 years ago

. Which function's graph has a vertex at (-1, -3) and contains the point (2, 15)? HELPPP PLEASEE

Mathematics

1 answer:

AlexFokin [52]3 years ago

5 0

Answer:

2(x+1)²-3

Step-by-step explanation:

Using the vertex formula we can write the follwoing equation

y=a(x+1)²-3

We need to solve for a

we know that when x= 2 y = 15

So we can write

15=a(2+1)²-3

15=9a-3

18=9a

a=2

Which means our final equation is

2(x+1)²-3

in standard form (just in case)

2x²+4x-1

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I tried to answer but I still would like to know what doesn't make sense.

Considering the identity:

$\sec^2\theta-\tan^2\theta=1 \implies |\sec\theta|\geq1$

$\forall\;\theta\in\mathbb{R}-\{(2n+1)\frac{\pi}{2}, n\in\mathbb{Z} \}$

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