In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Should we simplify or solve for m...?
Look at the picture it explains the answer
<h3>#End behaviour:-</h3>
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<h3>#Degree:-</h3>
Find nodes
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It's a parabola so it's the graph of a quadratic equation.
<h3>Real zeros</h3>
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