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77julia77 [94]
3 years ago
8

Find b and c so that (5,b,c) is orthogonal to both (1,2,3) and (1,-2,1)

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
{5+2b+3c=0
5−2b+c=0
adding both equations u get10+4c=0⇒c=−10/4=−5/2
then5−2b+(−5/2)=0⇒b=(5/2−5)/(−2)=5/2−5/4=5/4
MariettaO [177]3 years ago
4 0

Answer:  The answer is 3.75 and -2.5.

Step-by-step explanation: We are given to find the values of b and c if the vector (5, b, c) is orthogonal to (1, 2, 3) and (1, -2, 1).

We know that if two vectors are orthogonal, then their dot product is equal to zero. So, we have

(5, b, c).(1,2,3)=0\\\\\Rightarrow 5+2b+3c=0\\\\\Rightarrow 2b+3c=-5,~~~~~~~~~~~~~~~~~~~~(A)

and

(5,b,c).(1,-2,1)=0\\\\\Rightarrow 5-2b+c=0\\\\\Rightarrow -2b+c=-5.~~~~~~~~~~~~~~~~~~~~~(B)

Adding equations (A) and (B), we have

3c+c=-5-5\\\\\Rightarrow 4c=-10\\\\\Rightarrow c=-2.5,

and from (B), we have

-2b+2.5=-5\\\\\Rightarrow -2b=-7.5\\\\\Rightarrow b=3.75.

Thus, the value of b is 3.75 and the value of c is -2.5.

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vladimir2022 [97]

<u>Given</u>:

The given function is f(x)=4x^2+2x+6

We need to determine the value of the discriminant f and also to determine the distinct real number zeros of f.

<u>Discriminant</u>:

The discriminant can be determined using the formula,

\Delta = b^2-4ac

Now, we shall determine the discriminant of the function f(x)=4x^2+2x+6

Substituting the values in the formula, we have;

\Delta=(2)^2-4(4)(6)

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Thus, the value of the discriminant of f is -92.

<u>Distinct roots:</u>

The distinct zeros of the function f can be determined by

(1) If \Delta>0, then the function has 2 real roots.

(2) If \Delta=0, then the function has 2 real roots ( or one repeated root).

(3) If \Delta, then the function has 2 imaginary roots (or no real roots).

Since, the discriminant is \Delta=-92 \ < \ 0 , then the function has no real roots  or 2 imaginary roots.

Thus, the function has 2 imaginary roots.

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